What is the acceleration of a different speck of dust that is twice as far from the center of the disk?.
1 answer:
The acceleration of a different speck of dust is 40 m/s.
Since the radius is been given as double and angular velocity will be constant, we can calculate the centripetal acceleration as
a = (2r)ω²
If we substitute the given values of r= 2r , and ω²= 20m/s.
Then we have
Therefore, acceleration of a different speck of dust is 40 m/s.
<h3>What is centripetal acceleration?</h3>centripetal acceleration can be regarded as acceleration of a body that is traversing a circular path.
CHECK THE COMPLETE QUESTIONS;
A speck of dust on a spinning dvd has a centripetal accelera- tion of 20 m/s2.
a. what is the acceleration of a different speck of dust that is twice as far from the center of the disk?
Learn more about centripetal acceleration at;
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Answer:
The final speed of bicycle would be <u>27 m/s</u>².
Step-by-step explanation:
<u>Given</u> :
Initial velocity (u) = 15 m/s
<u>To</u><u> </u><u>Find</u> :
<u>Using</u><u> </u><u>Formula</u> :
v = final velocity
<u>Solution</u> :
Substituting the values in the formula to find the final velocity :
Hence, the final speed of bicycle would be 27 m/s².