3.
1 answer:
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Answer:
-7.90
Step-by-step explanation:
Let's write the null hypothesis (H0) and alternative hypothesis (Ha) from the claim statement
P = population proportion of adults who would erase all of their personal information online if they could
H_{0}:P=0.5
H1 P< 0.5
Let's write the given information:
n = sample size = 480
sample proportion =
formula of z test statistic for one sample proportion test is as follows:
plug the above values in the above formula we get
So that the test statistic value is -7.90 (Rounded up to two decimal places)
We cannot calculate the confidence interval without the sample size. However, for the second question, the sample size needed would be 49.
The formula we use is
To find the z-score:
Convert 98% to a decimal: 0.98
Subtract from 1: 1-0.98 = 0.02
Divide by 2: 0.02/2 = 0.01
Subtract from 1: 1-0.01 = 0.99
Using a z-table (http://www.z-table.com) we see that this value is closest to a z-score of 2.33.
Using the z-score, our standard deviation (9) and our margin of error (3), we have:
The formula we use is
To find the z-score:
Convert 98% to a decimal: 0.98
Subtract from 1: 1-0.98 = 0.02
Divide by 2: 0.02/2 = 0.01
Subtract from 1: 1-0.01 = 0.99
Using a z-table (http://www.z-table.com) we see that this value is closest to a z-score of 2.33.
Using the z-score, our standard deviation (9) and our margin of error (3), we have: