29*2.4-36.5= 33.1 hrs before the freight train cought up.
M=rise over run
27 over 36 in lowest terms
Or 27/36
Answer:
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Step-by-step explanation:
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Answer:
t≤ 9
Step-by-step explanation:
3.5+4t≤ 39.5
subtract 3.5 from each side
4t≤ 36
divide each side by 4
t≤ 9
You need to find the total distance and the total time. The total distance is two times the distance to school, 2d.s=d/t=>t=d/sWhere s is speed, d is distance and t is time. So the time taken to get to school is:d/s1and the time taken to get back is:d/s2so the total time is:d/s1+d/s2=d(1/s1+1/s2)So, as speed = distance/time, divide the total distance by the total time:2d/d(1/s1+1/s2)=2/(1/s1+1/s2)=2/(1/20+1/40)=80/3≈26.7km/hr
