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Sunny_sXe [5.5K]
3 years ago
10

What is the solution to the equation Negative (5 minus (a + 1)) = 9 minus (5 minus (2a minus 3))? a = –5 a = –3 a = 3 a = 5

Mathematics
1 answer:
Mariana [72]3 years ago
5 0

Answer:

<u>a = - 5.</u>

Step-by-step explanation:

The given equation is,

  • Negative (5 minus (a + 1)) = 9 minus (5 minus (2a minus 3))

We need to change it to its numerical form ⟶ - (5 - (a + 1)) = 9 - (5 - (2a - 3))

Now, by solving it...

-(5-(a+1))=9-(5-(2a-3))\\-\left(5-a-1\right)=9-\left(5-\left(2a-3\right)\right) \\-\left(4-a\right)=9-\left(5-\left(2a-3\right)\right) \\-4+a=9-\left(5-\left(2a-3\right)\right) \\-4+a=9-\left(5-2a-\left(-3\right)\right) \\-4+a=9-\left(5-2a+3\right) \\-4+a=9-\left(8-2a\right) \\-4+a=9-8-\left(-2a\right) \\-4+a=9-8+2a \\-4+a=1+2a \\-4+a-2a=1 \\-4-a=1 \\-a=1+4 \\-a=5 \\\boxed{a=-5 }

__________

Hope it helps!

\mathfrak{Lucazz}

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Step-by-step explanation:

Equation of a line is y = mx + c

where

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To find the equation of the line parallel to 3x - y = 14 we must first find the slope of 3x - y = 14.

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Comparing with the general equation above

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Equation of the line using point ( - 4 , -7) and slope 3 is

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We have the final answer as

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