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nydimaria [60]
3 years ago
13

What is 20 as a product of three primes

Mathematics
1 answer:
nikdorinn [45]3 years ago
8 0
2, 5, 2 i think.
sorry if it’s wrong!
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What is an equation of a line that passes through the point (-3 -7) and it’s parallel to the line 2x-3y=24
andrew-mc [135]

Answer:

y=(-2/3)x-9

Step-by-step explanation:

1) first put the equation in terms of y. You should get y=-(2/3)x-8.

2) parallel lines have the same slope so the slope for this line and the answer should be the same

3) using the form y=mx+b plug (-2/3) in as the slope or m

4) plug the point in to get your b value. you should have -7 =((-2/3)•(-3))+b

5) isolate the variable b and plug in your answer to the equation.

6 0
3 years ago
Find the slope of the line which is perpendicular to a line having a slope of 5/7
erica [24]

Answer:

-7/5

Step-by-step explanation:

5/7

= -7/5

3 0
3 years ago
According to government data, 75% of employed women have never been married. Rounding to 4 decimal places, if 15 employed women
blagie [28]

Answer:

We are given that According to government data, 75% of employed women have never been married.

So, Probability of success = 0.75

So, Probability of failure = 1-0.75 = 0.25

If 15 employed women are randomly selected:

a. What is the probability that exactly 2 of them have never been married?

We will use binomial

Formula : P(X=r) =^nC_r p^r q^{n-r}

At x = 2

P(X=r) =^{15}C_2 (0.75)^2 (0.25^{15-2}

P(X=2) =\frac{15!}{2!(15-2)!} (0.75)^2 (0.25^{13}

P(X=2) =8.8009 \times 10^{-7}

b. That at most 2 of them have never been married?

At most two means at x = 0 ,1 , 2

So,  P(X=r) =^{15}C_0 (0.75)^0 (0.25^{15-0}+^{15}C_1 (0.75)^1 (0.25^{15-1}+^{15}C_2 (0.75)^2 (0.25^{15-2}

 P(X=r) =(0.75)^0 (0.25^{15-0}+15 (0.75)^1 (0.25^{15-1}+\frac{15!}{2!(15-2)!} (0.75)^2 (0.25^{15-2})

P(X=r) =9.9439 \times 10^{-6}

c. That at least 13 of them have been married?

P(x=13)+P(x=14)+P(x=15)

={15}C_{13}(0.75)^{13} (0.25^{15-13})+{15}C_{14} (0.75)^{14}(0.25^{15-14}+{15}C_{15} (0.75)^{15} (0.25^{15-15})

=\frac{15!}{13!(15-13)!}(0.75)^{13} (0.25^{15-13})+\frac{15!}{14!(15-14)!} (0.75)^{14}(0.25^{15-14}+{15}C_{15} (0.75)^{15} (0.25^{15-15})

=0.2360

8 0
3 years ago
I really need some help. I need to find the inverse of this equation in the picture below. Thanks!
serg [7]

Answer:

y=81x^4+648x^3+1944x^2+2592x+1289

Step-by-step explanation:

1. Interchange x and y.

  • y=\frac{\sqrt[4]{x+7}}{3}-2
  • x=\frac{\sqrt[4]{y+7}}{3}-2

2. Then solve x=\frac{\sqrt[4]{y+7}}{3}-2 for y.

3. y=81x^4+648x^3+1944x^2+2592x+1289

I hope this helps.

4 0
3 years ago
What is the slope of the point (1÷4,3÷2)and (-1,-3)​
Viefleur [7K]

Step-by-step explanation:<u>The slope calculator helps find the slope of any line through two given ... the slope of the line passing through the points (3,8) and (-2, 10) . ... A 1/20 slope is one that rises by 1 unit for every 20 units traversed horizontally.</u>

<u />

3 0
3 years ago
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