All categories

2 years ago

Find the dimensions of a rectangle

Mathematics

1 answer:

gayaneshka [121]2 years ago

4 0

The length of the shorter side is 7 longer side is 12 7+7+12+12 is 38 and 7x12 is 84

You might be interested in

Delaney has a piggy bank that contains 4 pennies, 29 nickels, 13 dimes, and 12 quarters. Suppose one coin is selected at random.

Wittaler [7]

Answer:

The chances are very high because there are more nickels then there quarters, dimes, and pennies.

Step-by-step explanation:

4 0

2 years ago

Today you jogged 1/3 of a mile

MakcuM [25]

You jogged 2/3 of a mile. 1/3 plus 1/3 equals 2/3.

5 0

3 years ago

Practice working with reflections.

Alinara [238K]

Answer: The rule of the reflection is rx-axis(x, y) → (x, –y) ⇒ 3rd answer

Step-by-step explanation:

Let us revise the reflection on the axes

If point (x , y) reflected across the x-axis , then its image is (x , -y) , the rule of reflection is rx-axis (x , y) → (x , -y)

If point (x , y) reflected across the y-axis , then its image is (-x , y) , the rule of reflection is ry-axis (x , y) → (-x , y)

In Δ LMN

∵ L = (-4 , 2)

∵ M = (-5 , 4)

∵ N = (-2 , 3)

In ΔL'M'N'

∵ L' = (-4 , -2)

∵ M' = (-5 , -4)

∵ N' = (-2 , -3)

The signs of y-coordinates of the vertices of Δ LMN are changed, that means Δ LMN are reflected across the x-axis

∵ The y-coordinate of L is 2 and the y-coordinate of L' is -2

∵ The y-coordinate of M is 4 and the y-coordinate of M' is -4

∵ The y-coordinate of N is 3 and the y-coordinate of N' is -3

∴ Δ LMN is reflected across the x-axis

∴ The image of point (x , y) is (x , -y)

3 0

3 years ago

Read 2 more answers

Find the kissing lengths of the sides of the triangle.

alina1380 [7]

Answer: The last option.

Step-by-step explanation:

The triangle shown in the figure attached is a right triangle.

1. You can calculate the lenght a as following:

$sin\alpha=\frac{opposite}{hypotenuse}$

$opposite=a\\hypotenuse=6in\\\alpha=30\°$

Substitute values and solve for a. Then, you obtain:

$sin(30\°)=\frac{a}{6in}\\a=6in*sin(30\°)\\a=3in$

2. You can calculate the lenght b as following:

$cos\alpha=\frac{adjacent}{hypotenuse}$

$adjacent=b\\hypotenuse=6in\\\alpha=30\°$

Substitute values and solve for b. Then, you obtain:

$cos(30\°)=\frac{b}{6in}\\b=6in*cos(30\°)$

$b=3\sqrt{3}in$

3 0

3 years ago

Help I will be marking brainliest!!!

weeeeeb [17]

This was the value I obtained

7 0

2 years ago