1a) 8 / (1/2) = 16 * 3 = 48
1b) 3sqrt(49) = 3 * 7 = 21
1c) (5+2)(-8) / (-2)^3 -3
(7*-8) / (-8 -3)
-56/-11
56/11
Yes, because it is continuous on [0,2] and differentiable on (0,2), the theorem states that there must exist some value c where a line tangent to c is parallel to the secant line through 0 and 2.
This is the concept of relative speed; We are required to calculate the speed of the car and the bicycle.
Distance between the car and Bicycle=374 miles
Time they met=5.5 hr
Speed traveled by bicycle=x
Speed traveled by car=x+33.4334
Relative speed=x+(x+33.4334)=(2x+33.4334) mph
Distance=speed*time
374=(2x+33.4334)*5.5
374=11x+183.8837
collecting like term we get:
374-183.8837=11x
11x=190.1163
thus;
x=(190.1163)/(11)
x=17.2833 mph
thus the speed of the bicycle was x=17.2833 mph
The speed of the car was (x+33.4334)=(17.2833+33.4334)=50.7167 mph
4/6 or 2/3. All you need to do is add the amount of blue and red sides from the cube and divide it by the total number of sides on a cube.
You can also say 66%
Hope this helps!! :)
I think x equals 54
Hope this helps
