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2 years ago

What is the best approximation of the volume, in cubic units, of a cylinder of diameter 10 and height 10?

Mathematics

1 answer:

Ksenya-84 [330]2 years ago

7 0

Answer:

785.4 units³ (nearest tenth)

Step-by-step explanation:

volume of a cylinder = $\pi$ r²h

where r is the radius and h is the height

diameter of a circle = 2r

where r is the radius

Therefore, 10 = 2r ⇒ r = 5

Therefore, volume = $\pi$ x 5² x 10 = 250 $\pi$ = 785.4 units³ (nearest tenth)

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The first term of a geometric sequence is −2 and the common ratio is 3. What is the fourth term of the sequence?

Nat2105 [25]

Answer: -54

Step-by-step explanation:

The question is the first term of a geometric sequence is −2 and the common ratio is 3. The formula for finding the nth term of a geometric sequence is: ar^n-1

where,

a = first term = -2

r = common ratio = 3

n = number of terms = 4

The solution has been attached. The answer is -54

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3 years ago

What is the answer <br><br> 10(4 - 3i) =

Elina [12.6K]

Answer:

40-30i

Step-by-step explanation:

Use distributive property.

7 0

2 years ago

Read 2 more answers

Pretty lost WILL GIVE FIVE STARS

Artemon [7]

Being able to do this problem hinges mainly on your knowing the definitions of the trig functions and being able to read side lengths from the given diagram.

csc theta = hypotenuse / opp side = 4 / √(4^2 + 5^2) = 4 / √41.

sin theta is the reciprocal of csc theta, or √41 / 4.

cot theta is adj side / opp side = 5/4.

3 0

3 years ago

A brand of clay brick tiles has the dimensions 3 5 8 by 7 5 8 by 1 2 inch. These thin bricks are commonly used for floors. Estim

raketka [301]

Answer: The cost to tile the floor is $318.24.

Step-by-step explanation:

Since we have given that

Dimensions of floor is 12 by 17 foot.

So, Area of floor would be

$12\times 17\\\\=204\ sq.\ foot$

As we know that 1 foot = 12 inch

So, Area of floor would be

$204\times (12)^2\\\\=204\times 144\\\\=29376\ sq.\ foot$

Dimension of brick tiles is given by

$3\dfrac{5}{8}\ by\ 7\dfrac{5}{8}\ by\ \dfrac{1}{2}$

So, Area of brick tiles is given by

$2(lb+bh+lh)\\\\=2(\dfrac{29}{8}\times \dfrac{61}{8}+\dfrac{61}{8}\times \dfrac{1}{2}+\dfrac{29}{8}\times \dfrac{1}{2})\\\\=2(\dfrac{1769}{64}+\dfrac{61}{16}+\dfrac{29}{16})\\\\=2\times \dfrac{1769+244+116}{64}\\\\=\dfrac{2129}{32}$