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2 years ago

Write a whole number that rounds 2000 if we round it to the nearest hundred

Mathematics

1 answer:

Brilliant_brown [7]2 years ago

6 0

Answer:

1,995 would round to 2,000

Step-by-step explanation:

1,995 is 5 away from 2,000 so if you were rounding to the nearest hundred 2,000 would be it

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Maddy lleva un bote con bebida para deportistas; el bote de 5 55 litros pesa 7 , 5 kg 7,5 kg7, comma, 5, start text, space, k, g

Kaylis [27]

Answer: $3\ kilograms$

Step-by-step explanation:

It is important to remember that, by definition, proportional relationships have the following form:

$y=kx$

Where "k" is the constant of proportionality.

We know that Maddy assume that the relation between the volume and the weight is proportional.

Then, let be "V" the volume in liters and "w" the weight in kilograms.

We can write the following equation:

$V=kw$

So, if the boat of 555 liters weights 7.5 kilograms, we can find "k":

$555 =k(7)\\\\k=\frac{555}{7}\\\\k=74$

In order to solve the exercise, substitute the value of "k" and $V=222$ into the equation and solve for "w". Then:

$222=(74)w\\\\\frac{222}{74}=w\\\\w=3$

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4 years ago

A parallelogram has an area of 216.24 cm 2 2 and a height of 15.9 cm. How long is the base of the parallelogram? Enter your answ

Studentka2010 [4]

The base would by 13.6 because 13.6 * 15.9 = 216.24

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4 years ago

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Which inequality represents all values of x for which the product below is defined?

inysia [295]

$\sqrt{5x}\cdot\sqrt{x+4}\\\\5x\geq0\ \wedge\ x+4\geq0\\x\geq0\ \wedge\ x\geq-4\Righarrow x\geq0\\\\Answer:B.$

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4 years ago

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What is the x-value of the solution to this system of equations?<br><br>4x+2y=10<br>x=y+13

Kobotan [32]

The value of x is 6.

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3 years ago

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What is the value of f (6) ?

Marta_Voda [28]

$\huge{ \boxed{ \tt{Solution :-}}}$

$\sf{f(x) = \dfrac{ x^2 - 4x }{20}}$

$\sf{What\: is\: the\: value \:of \: f(6)?}$

Now we solving it :

$\sf { : \implies{f(x) = \dfrac{ x^2 - 4x }{20}}} \\ \\ \sf { : \implies{f(6) = \dfrac{ 6^2 - 4 \times 6}{20}}} \\ \\ \sf { : \implies{f(6) = \dfrac{ 36 - 24}{20}}} \\ \\ \sf { : \implies{f(6) = \dfrac{ 12}{20}}} \\ \\ :\implies{\boxed {\tt{f(6) = \dfrac{ 3}{5}}}}$

$\bf {\therefore{The\:value\:of\:f (6)\:is\:\dfrac{ 3}{5}.}}$

$\rule {307}{2}$

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3 years ago