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Temka [501]
1 year ago
10

Six years ago, Lucia’s age was 1/3 the age she will be in 6 years. How old is Lucia now? Enter an integer.

Mathematics
1 answer:
Katen [24]1 year ago
7 0

Answer:

Lucia is 12 years old now

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Walt is mixing fruit punch for a party. He combines 1 gallon 2 quarts 3 pints of orange juice, 1 gallon 3 quarts 7 pints of pine
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1 gal    2 qts    3 pts
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3 gal    8 qts    13 pts

1 pt = 0.5 qts...so 12 pts = 12* 0.5 = 6...so now we have :
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6 gal   2 qts   1 pt <===
7 0
3 years ago
A cafe sells puffs. 5/9 are beef and 1/3 are chicken. The remaining 18 are tuna. Calculate 1. What fraction of the puffs are tun
Ksivusya [100]
Let n be the total number of puffs. Now we can write:
n=\frac{5}{9}n+\frac{1}{3}n+18
Adding the fractional value of n, we get:
n=\frac{5+3}{9}n+18
Simplifying and rearranging gives us:
n-\frac{8}{9}n=18
Therefore we can simplify to get:
\frac{1}{9}n=18
and finally
n=18\times9=?
The fraction of the puff that are tuna is found from:
\frac{18}{18\times9}=\frac{1}{9}
7 0
4 years ago
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you pick a number between 1,000 and 5,000 then you flip a coin identify if the two events are independent or dependent explain
Lelu [443]
Independent one has nothing to with the other

7 0
3 years ago
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The mass of a teapot and 4 cups is 1,280 grams. The mass of the same teapot and 10 cups is 2,720 grams. Each cup has the same ma
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Answer:

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Step-by-step explanation:

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4 0
3 years ago
A person stands 10 meters east of an intersection and watches a car driving towards the intersection from the north at 13 meters
In-s [12.5K]

Answer:

Therefore the rate change of distance between the car and the person at the instant, the car is 24 m from the intersection is 12 m/s.

Step-by-step explanation:

Given that,

A person stand 10 meters east of an intersection and watches a car driving towards the intersection from the north at 13 m/s.

From Pythagorean Theorem,

(The distance between car and person)²= (The distance of the car from intersection)²+ (The distance of the person from intersection)²+

Assume that the distance of the car from the intersection and from the person be x and y at any time t respectively.

∴y²= x²+10²

\Rightarrow y=\sqrt{x^2+100}

Differentiating with respect to t

\frac{dy}{dt}=\frac{1}{2\sqrt{x^2+100}}. 2x\frac{dx}{dt}

\Rightarrow \frac{dy}{dt}=\frac{x}{\sqrt{x^2+100}}. \frac{dx}{dt}

Since the car driving towards the intersection at 13 m/s.

so,\frac{dx}{dt}=-13

\therefore \frac{dy}{dt}=\frac{x}{\sqrt{x^2+100}}.(-13)

Now

\therefore \frac{dy}{dt}|_{x=24}=\frac{24}{\sqrt{24^2+100}}.(-13)

               =\frac{24\times (-13)}{\sqrt{676}}

               =\frac{24\times (-13)}{26}

               = -12 m/s

Negative sign denotes the distance between the car and the person decrease.

Therefore the rate change of distance between the car and the person at the instant, the car is 24 m from the intersection is 12 m/s.

8 0
3 years ago
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