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Naddik [55]
2 years ago
9

The depth of Lake Carl is about 1 1/8 miles. Lake Susan is 3 times as deep as Lake Carl. Lake Wayne is 2 times as deep as Lake S

usan. How much deeper is Lake Wayne than Lake Susan?
Mathematics
1 answer:
Step2247 [10]2 years ago
5 0

Answer:

3\frac{3}{8}

Step-by-step explanation:

Let LC be Lake Carl, LS be Lake Susan, and LW be Lake Wayne

First, find a way to denote all the lakes using one lake depth

LC = 1 1/8

LS = 3LC

LW = 3LS or 6LC

Then write an equation.

LW - LS = 6LC - 3LC = 3LC

Substitute LC and calculate.

3 * 1 1/8 = 3 3/8

Hope this helps :)

Have a great day!

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Sholpan [36]

Answer:

Yearly budget= $3840

Monthly budget= $320

Step-by-step explanation:

His budget will be calculated first by rounding off to the nearest$10 all his monthly spending.

For groceries= $176.47

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For phone =$ 78.66

Round off = $80.00

For gas = $62.37

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His total round off = $180+$80+$60

His total round off = $320

Before the round off, his total spending was $176.47+$78.66+$62.37

= $317.5

So his monthly budget should be $320

And yearly budget =$ 320*12

Yearly budget= $3840

4 0
3 years ago
The graphs below have the same shape the equation of the red graph is f(x) =x^2. What is the equation of the blue graph?
daser333 [38]

Answer:

G(x)=(x-6)^2

which agrees with the answer D of your options

Step-by-step explanation:

Notice that the graph of G(x) has the initial graph shifted horizontally to the right in 6 units, therefore such horizontal shift is accomplished by subtracting the 6 units from the x-variable in the original expression:

G(x)=(x-6)^2

3 0
3 years ago
What is the value of x
pochemuha

This is the isosceles triangle. Therefore, the angles at the base are congruent.

We know that the sum of the measures of the angles in a triangle is 180°.

Therefore we have the equation:

38^o+x^o+x^o=180^o

38^o+2x^o=180^o        <em>subtract 38 from both sides</em>

2x^o=142^o       <em>divide both sides by 2</em>

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<h3>Answer: x = 71.</h3>
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Alla [95]

Answer:

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Step-by-step explanation:

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Aleksandr-060686 [28]
This may look a little confusing but all you have to do is plug the equation given for h(x) which is 2x-5 in to the h(x) area in the equation where it says h(x) + g(x).

So far that’s (2x-5) + g(x)

Then,

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