If each of the branches has half the area of the aorta, its linear scale factor is the square root of 1/2, or (√2)/2.
The diameter of one of the branches is (da×√2)/2.
Answer:
x=6
Step-by-step explanation:
5x+4+8x-3=79
=>13x=79-4+3
=>13x=78
=>x=78/13
=>x=6
|------|------|------|-----|------|
Answer:
C = 28.048
Step-by-step explanation:
Circumference = 2pi(r)
Area = pi(r)^2
62.6 = pi(r)^2
r^2 = 62.6/pi
r^2 = 19.926
r = 4.464
Therefore, circumference = 2pi(4.464)
= 28.048
To find W⊥, you can use the Gram-Schmidt process using the usual inner-product and the given 5 independent set of vectors.
<span>Define projection of v on u as </span>
<span>p(u,v)=u*(u.v)/(u.u) </span>
<span>we need to proceed and determine u1...u5 as: </span>
<span>u1=w1 </span>
<span>u2=w2-p(u1,w2) </span>
<span>u3=w3-p(u1,w3)-p(u2,w3) </span>
<span>u4=w4-p(u1,w4)-p(u2,w4)-p(u3,w4) </span>
<span>u5=w5-p(u4,w5)-p(u2,w5)-p(u3,w5)-p(u4,w5) </span>
<span>so that u1...u5 will be the new basis of an orthogonal set of inner space. </span>
<span>However, the given set of vectors is not independent, since </span>
<span>w1+w2=w3, </span>
<span>therefore an orthogonal basis cannot be found. </span>
