Since

, you can eliminate this part.
So you're left with

⇒

⇒

which is about -9.11111...
Answer:
0.0549
0.7617
0.2383
Step-by-step explanation:
Given that:
Probability that incoming email is spam ;
P(spam) = 0.38
If three emails are in my inbox, what is the probability that:
A. All three messages are spam.
P(1st message being spam) * p(second message being spam) * p(3rd message being spam)
= (0.38) * (0.38) * (0.38)
= 0.054872
= 0.0549
B. At least one of the three messages are spam.
1 - p(none of the 3 messages are spam)
P(none of the 3 messages are spam)
P(not spam) = 1 - p(spam) = 1 - 0.38 = 0.62
1 - [P(not spam) * p(not spam) * p(not spam)]
1 - (0.62 * 0.62 * 0.62)
= 1 - 0.238328
= 0.761672
= 0.7617
C. None of the three messages are spam.
P(not spam) = 1 - p(spam) = 1 - 0.38 = 0.62
P(not spam) * p(not spam) * p(not spam)
(0.62 * 0.62 * 0.62)
= 0.238328
= 0.2383
Answer:
0.20 = 1/5 or 20%
0.30 = 3/10 or 30%
The first thing you should do is to add -2q on both sides of the equation and then add +7 on both sides so you will have:
6q - 2q = 29 +7
4q = 36 so q is equal to 36/4 or 9 :)))
i hope this is helpful
have a nice day
Answer:
RQ = 9.
Step-by-step explanation:
m < RPQ = 180 - 90 - 75 = 15 degrees
m < PQM = 75 - 60 = 15 degrees.
So triangle PMQ is isosceles so side PM is congruent to side MQ, therefore MQ = 18.
Triangle RQM is a 30-60-90 triangle with RQ the shortest leg (because it is opposite the lowest angle) so that makes RQ = 1/2 of MQ. (The sides in a 30-60-90 triangle are in the ratio 1:sqrt3:2)
RQ = 1/2 * 18 = 9.