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2 years ago

Graph AB¯¯¯¯¯¯¯¯ with endpoints A(−6, −1) and B(−5, 3) and its image after the composition.

Mathematics

1 answer:

Alona [7]2 years ago

7 0

Answer:

Step-by-step explanation:

AB=-6×-5÷-1×3

AB= 30÷-3

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Write the given trinomial if possible as a square of a binomial or as an expression opposite to a square of a binomial:

Ksenya-84 [330]

$\frac{4}{9}b^2 + 0.4bc + 0.09c^2 = \frac{4}{9}b^2 + \frac{4}{10}bc + \frac{9}{100}c^2 = (\frac{2}{3}b + \frac{3}{10}c)^2$

7 0

3 years ago

Required information Skip to question A die (six faces) has the number 1 painted on two of its faces, the number 2 painted on th

grigory [225]

Answer:

The change to the face 3 affects the value of P(Odd Number)

Step-by-step explanation:

Analysing the question one statement at a time.

Before the face with 3 is loaded to be twice likely to come up.

The sample space is:

$S = \{1,1,2,2,2,3\}$

And the probability of each is:

$P(1) = \frac{n(1)}{n(s)}$

$P(1) = \frac{2}{6}$

$P(1) = \frac{1}{3}$

$P(2) = \frac{n(2)}{n(s)}$

$P(2) = \frac{3}{6}$

$P(2) = \frac{1}{2}$

$P(3) = \frac{n(3)}{n(s)}$

$P(3) = \frac{1}{6}$

P(Odd Number) is then calculated as:

$P(Odd\ Number) = P(1) + P(3)$

$P(Odd\ Number) = \frac{1}{3} + \frac{1}{6}$

Take LCM

$P(Odd\ Number) = \frac{2+1}{6}$

$P(Odd\ Number) = \frac{3}{6}$

$P(Odd\ Number) = \frac{1}{2}$

After the face with 3 is loaded to be twice likely to come up.

The sample space becomes:

$S = \{1,1,2,2,2,3,3\}$

The probability of each is:

$P(1) = \frac{n(1)}{n(s)}$

$P(1) = \frac{2}{7}$

$P(2) = \frac{n(2)}{n(s)}$

$P(2) = \frac{3}{7}$

$P(3) = \frac{n(3)}{n(s)}$

$P(3) = \frac{1}{7}$

$P(Odd\ Number) = P(1) + P(3)$

$P(Odd\ Number) = \frac{2}{7} + \frac{1}{7}$

Take LCM

$P(Odd\ Number) = \frac{2+1}{7}$

$P(Odd\ Number) = \frac{3}{7}$

Comparing P(Odd Number) before and after

$P(Odd\ Number) = \frac{1}{2}$ --- Before

$P(Odd\ Number) = \frac{3}{7}$ --- After

<em>We can conclude that the change to the face 3 affects the value of P(Odd Number)</em>

7 0

3 years ago

Find the Value of a and b i dare u

fenix001 [56]

Well it's a dare so I guess I'll do it.

3 0

3 years ago

Samantha has 1/3 gallon of milk left and wants to make 55 smoothies. If she wants to use the same amount of milk in each smoothi

Bingel [31]

Answer:

She can put 1/165 in one smoothie.

Step-by-step explanation:

1/3 divided by 55/1

1/3 x 1/55 = 1/165

Hope this helps! :)

plz make me the Brainiest

6 0

3 years ago

Each student wrote a two-step equation. Peter wrote the equation 4x-2=10, and Andres wrote the equation 16x-8=40. The teacher lo

natima [27]

Both variables (x) are 3.

4×3=12
12-2=10

16×3=48
48-8=40

3 fits the variable of the missing number.

8 0

2 years ago