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zhannawk [14.2K]
2 years ago
11

Graph AB¯¯¯¯¯¯¯¯ with endpoints A(−6, −1) and B(−5, 3) and its image after the composition.

Mathematics
1 answer:
Alona [7]2 years ago
7 0

Answer:

<h3>-10⇜</h3>

Step-by-step explanation:

AB=-6×-5÷-1×3

AB= 30÷-3

<h3>AB= -10⇚</h3>

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Find the midpoint of segment AB given. A (-3, 2) and B (3, -2)
Tasya [4]

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8 0
3 years ago
What is ?5/8 times ?.2 and equals ?8
aliya0001 [1]
First you put a 1 under the 2.Then you multiply 85*2 and you get 170.Next you multiply 8.2*1 and you get 8.2.Finally, you divide 170 by 8.2 and get 20.73.

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Hope that helped.
7 0
3 years ago
Melissa can walk 1 mile in 22 minutes. If she walks the same rate for 66 minuets, how many miles has the walked ?
Zielflug [23.3K]

Answer: 3 miles

Step-by-step explanation:

5 0
3 years ago
Read 2 more answers
Help lol! the explanation is on the bottom!!
Slav-nsk [51]

Answer:

1 =80

2 =100

3 =80

4 =100

6 = 100

7 =80

8 =100

Step-by-step explanation: since 5 and 7 are the same, if u slide the bottom up to the top, 1 and 3 would be the same as 5 and 7

2,4,6,and 8 are 180-80 which equals 100

3 0
3 years ago
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In 2002, there were 972 students enrolled at Oakview High School. Since then, the number of students has increased by 1.5% each
Katarina [22]

Answer:

The number of student increased each year by 986.58.

Step-by-step explanation:

Given : In 2002, there were 972 students enrolled at Oakview High School.

To find : The number of students has increased by 1.5% each year ?

Solution :

Using the exponential growth function,

P(t)=P_o(1+r)^t

Here, P_o=972 is the initial population

r=1.5%=0.015 is the rate

t=1 time

P(t)=972(1+0.015)^1

P(t)=972(1.015)

P(t)=986.58

i.e. the number of student increased each year by 986.58.

3 0
3 years ago
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