Simplify
−
3
(
j
+
3
)
+
9
j
-
3
(
j
+
3
)
+
9
j
.
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Simplify each term.
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−
3
j
−
9
+
9
j
<
−
15
-
3
j
-
9
+
9
j
<
-
15
Add
−
3
j
-
3
j
and
9
j
9
j
.
6
j
−
9
<
−
15
6
j
-
9
<
-
15
Move all terms not containing
j
j
to the right side of the inequality.
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Add
9
9
to both sides of the inequality.
6
j
<
−
15
+
9
6
j
<
-
15
+
9
Add
−
15
-
15
and
9
9
.
6
j
<
−
6
6
j
<
-
6
Divide each term in
6
j
<
−
6
6
j
<
-
6
by
6
6
and simplify.
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Divide each term in
6
j
<
−
6
6
j
<
-
6
by
6
6
.
6
j
6
<
−
6
6
6
j
6
<
-
6
6
Simplify the left side.
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j
<
−
6
6
j
<
-
6
6
Simplify the right side.
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j
<
−
1
j
<
-
1
The result can be shown in multiple forms.
Inequality Form:
j
<
−
1
j
<
-
1
Interval Notation:
(
−
∞
,
−
1
)
The largest number that 8c could be is -15
36cm³
Step-by-step explanation:
Volume= mass
density
Answer:
Hypotenuse
Step-by-step explanation:
For this problem you are given the vertical and horizontal sides of the triangle. The flagpole (6.5 meters) is the up-and-down triangle side and the distance from the hook to the flagpole is the base (5.2 meters) of the triangle.
Hope this helps!
Probability he doesn't make a free shot = 10/10 - 7/10 = 3/10
Doesn't first time, does second time, so...
3/10 x 7/10 = 21/100
