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baherus [9]
2 years ago
7

Given the following exponential function, identify whether the change represents growth or decay, and determine the percentage r

ate of increase or decrease.
y=570(0.98)^x
Mathematics
1 answer:
IceJOKER [234]2 years ago
4 0

Answer:

decay

2% decrease

Step-by-step explanation:

The growth factor is the base of the exponent: 0.98. Its relation to the rate of change is ...

 growth factor = 1 + rate of change

 0.98 = 1 + (-0.02)

So, the rate of change is -0.02 = -2%. Since the rate of change is a 2% decrease, it represents decay.

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Answer:

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Step-by-step explanation:

Distance travelled on graph = AB + BC + CD + DA  

AB = CD  = (3 +2) = 5

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Distance on graph = 2 × 5 + 2 × 4 = 10 + 8 = 18 spaces = 18 blocks

Bridgette jogs \boxed{\textbf{18 blocks}}each day.

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3 years ago
Olivia is making bead bracelets for her friends. She can make 3 bracelets in 15 minutes.Now find the constant of proportionality
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Answer:

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Use addition to solve the linear system of equations. Include all of your work in your final answer.
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Step-by-step explanation:

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3 years ago
Someone please be awesome and help me please :(
solong [7]

Answer:

(x+\frac{b}{2a})^2+(\frac{4ac}{4a^2}-\frac{b^2}{4a^2})=0

(x+\frac{b}{2a})^2=\frac{b^2-4ac}{4a^2}

x=\frac{-b}{2a} \pm \frac{\sqrt{b^2-4ac}}{2a}

Step-by-step explanation:

x^2+\frac{b}{a}x+\frac{c}{a}=0

They wanted to complete the square so they took the thing in front of x and divided by 2 then squared.  Whatever you add in, you must take out.

x^2+\frac{b}{a}x+(\frac{b}{2a})^2+\frac{c}{a}-(\frac{b}{2a})^2=0

Now we are read to write that one part (the first three terms together) as a square:

(x+\frac{b}{2a})^2+\frac{c}{a}-(\frac{b}{2a})^2=0

I don't see this but what happens if we find a common denominator for those 2 terms after the square.  (b/2a)^2=b^2/4a^2 so we need to multiply that one fraction by 4a/4a.

(x+\frac{b}{2a})^2+\frac{4ac}{4a^2}-\frac{b^2}{4a^2}=0

They put it in ( )

(x+\frac{b}{2a})^2+(\frac{4ac}{4a^2}-\frac{b^2}{4a^2})=0

I'm going to go ahead and combine those fractions now:

(x+\frac{b}{2a})^2+(\frac{-b^2+4ac}{4a^2})=0

I'm going to factor out a -1 in the second term ( the one in the second ( ) ):

(x+\frac{b}{2a})^2-(\frac{b^2-4ac}{4a^2})=0

Now I'm going to add (b^2-4ac)/(4a^2) on both sides:

(x+\frac{b}{2a})^2=\frac{b^2-4ac}{4a^2}

I'm going to square root both sides to rid of the square on the x+b/(2a) part:

x+\frac{b}{2a}=\pm \sqrt{\frac{b^2-4ac}{4a^2}}

x+\frac{b}{2a}=\pm \frac{\sqrt{b^2-4ac}}{2a}

Now subtract b/(2a) on both sides:

x=\frac{-b}{2a} \pm \frac{\sqrt{b^2-4ac}}{2a}

Combine the fractions (they have the same denominator):

x=\frac{-b \pm \sqrt{b^2-4ac}}{2a}

6 0
3 years ago
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