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3 years ago

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Consider the following equation.

1 answer:

Natali [406]3 years ago

7 0

$\\ \tt\longmapsto 6(-x)+4=3x+1$

$\\ \tt\longmapsto -6x+4=3x+1$

$\\ \tt\longmapsto -6x-3x=1-4$

$\\ \tt\longmapsto -9x=-3$

$\\ \tt\longmapsto x=\dfrac{1}{3}$

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Use the method of undetermined coefficients to find the general solution to the de y′′−3y′ 2y=ex e2x e−x

djverab [1.8K]

I'll assume the ODE is

$y'' - 3y' + 2y = e^x + e^{2x} + e^{-x}$

Solve the homogeneous ODE,

$y'' - 3y' + 2y = 0$

The characteristic equation

$r^2 - 3r + 2 = (r - 1) (r - 2) = 0$

has roots at $r=1$ and $r=2$ . Then the characteristic solution is

$y = C_1 e^x + C_2 e^{2x}$

For nonhomogeneous ODE (1),

$y'' - 3y' + 2y = e^x$

consider the ansatz particular solution

$y = axe^x \implies y' = a(x+1) e^x \implies y'' = a(x+2) e^x$

Substituting this into (1) gives

$a(x+2) e^x - 3 a (x+1) e^x + 2ax e^x = e^x \implies a = -1$

For the nonhomogeneous ODE (2),

$y'' - 3y' + 2y = e^{2x}$

take the ansatz

$y = bxe^{2x} \implies y' = b(2x+1) e^{2x} \implies y'' = b(4x+4) e^{2x}$

Substitute (2) into the ODE to get

$b(4x+4) e^{2x} - 3b(2x+1)e^{2x} + 2bxe^{2x} = e^{2x} \implies b=1$

Lastly, for the nonhomogeneous ODE (3)

$y'' - 3y' + 2y = e^{-x}$

take the ansatz

$y = ce^{-x} \implies y' = -ce^{-x} \implies y'' = ce^{-x}$

and solve for $c$ .

$ce^{-x} + 3ce^{-x} + 2ce^{-x} = e^{-x} \implies c = \dfrac16$

Then the general solution to the ODE is

$\boxed{y = C_1 e^x + C_2 e^{2x} - xe^x + xe^{2x} + \dfrac16 e^{-x}}$

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1 year ago

Write a real-life word problem that involves one-variable equation. Discuss how you would go about solving this problem.

GalinKa [24]

Answer:

A waiter at a restaurant earns 10 dollars per hour. How much money is earned in 4 hours?

Equation: m = 10h

m = money earned

h = hours worked

Plug in 4 for (h)

m = 10(4)

m = 40 dollars

The waiter earns 40 dollars in 4 hours.

Step-by-step explanation:

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A man selling computer parts realizes that when he sells 16 computer parts, his earning is $1700. When he sells 56 computer part

natta225 [31]

We need to find the unit rate. To do so, divide the amount of money he makes by the number of parts sold. 1,700 / 16 = 106.25. So, if the man sells one computer part, he gets $106.25. To find the price of 30 parts, multiply 106.25 by 30. 106.25 * 30 = $3,187.50

The man will make $3,187.50 if he sells 30 parts.

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sleet_krkn [62]

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