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3 years ago

Find missing number sequence 1,2,5,10,13,,,58,61

Mathematics

1 answer:

lys-0071 [83]3 years ago

7 0

The pattern is *2 +3 *2 +3 *2 +3 .... 1 *2 = 2 , 2+3 = 5 , 5 *2 = 10, 10 +3 = 13, 13*2 = ?...

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PLEASE HELP I ONLY HAVE 3 MINUTES LEFT :(

Lemur [1.5K]

Answer:

D, -5x +12

Step-by-step explanation:

y = -5x + b

2 = -5(2) + b

2 = -10 + b

b =12

y= -5x +12

3 0

3 years ago

Evaluate B ^2 for B = -4.

Vesnalui [34]

B^2 = what when B = -4

Note: B^2 means B square or B to the second power. The power, in this case 2, tells us how many times to multiply the base B by.

So, B^2 = B • B.

Replace B with -4.

(-4)^2 = (-4)(-4) = 16.

We conclude by saying that B^2 = 16 when B is - 4.

Note: The answer is the same when B is 4.

4 0

4 years ago

Someone please do this one for me !!!!

oee [108]

Answer:

Plot the points in black and connect them.

Plot the point in blue and count up 3 and to the right 1. Plot and connect the points.

Step-by-step explanation:

Using your cursor/mouse, you will first choose the color black. Then you will plot the points given to you (2,2) and (5,8) by first finding the x-coordinate of (x,y). Start at 2 on the x-axis. Follow the grid line up two units so you will also be at the 2 on the y-axis. Plot or draw a dot/circle on this grid line. Go back to the x-axis and start again at 5 on the x-axis. Follow the grid line up eight units so you will also be at the 8 on the y-axis. Plot or draw a dot/circle on this grid line. Connect the dots for your line.

Using your cursor/mouse, you will choose the color blue. Then you will plot the point given to you (10,5) by first finding the x-coordinate of (x,y). Start at 10 on the x-axis. Follow the grid line up five units so you will also be at the 5 on the y-axis. Plot or draw a dot/circle on this grid line. Instead of plotting another point. This time you will count from the blue point up three units and over to the right one. Mark this grid line as a point. Now connect them.

6 0

4 years ago

Given: F(x) = x +3 ; G(x) = 2x^2 -4 Find (f*g)(x)<br><br>I seriously need help with this

Lana71 [14]

Step-by-step explanation:

just subscribe the value of x thn solve

after that put it in the function

3 0

3 years ago

Read 2 more answers

Write the polynomial as a square of a binomial or as an expression opposite to a square of a binomial:

spayn [35]

Answer:

A) $0.25x^2-0.6xy+0.36y^2=\left(0.5x-0.6y\right)^2$

B) $-a^2+0.6a-0.09=-\left(10a-3\right)^2$

C) $\frac{9a^4}{16}+a^3+\frac{4a^2}{9}=a^2(\left(9a+8\right)^2)$

D) $-16m^2-24mn -9n^2=-\left(4m+3n\right)^2$

Step-by-step explanation:

The square of a binomial is the sum of: the square of the first terms, twice the product of the two terms, and the square of the last term.

$(a+b)^2 = a^2 + 2ab + b^2\\\\(a-b)^2 = a^2 - 2ab + b^2$

To find the square of the binomial of the following polynomials you must:

A) $0.25x^2-0.6xy+0.36y^2$

Apply radical rule: $a=\left(\sqrt{a}\right)^2$

$0.25=\left(\sqrt{0.25}\right)^2\\0.36=\left(\sqrt{0.36}\right)^2$

$\left(\sqrt{0.25}\right)^2x^2-0.6xy+\left(\sqrt{0.36}\right)^2y^2$

Apply exponent rule: $a^mb^m=\left(ab\right)^m$

$\left(\sqrt{0.25}\right)^2x^2=\left(\sqrt{0.25}x\right)^2\\\left(\sqrt{0.36}\right)^2y^2=\left(\sqrt{0.36}y\right)^2$

$\left(\sqrt{0.25}x\right)^2-0.6xy+\left(\sqrt{0.36}y\right)^2$

Rewrite $0.6xy$ as $2\cdot \:0.5x\cdot \:0.6y$

$\left(\sqrt{0.25}x\right)^2-2\cdot \:0.5x\cdot \:0.6y+\left(\sqrt{0.36}y\right)^2$

Apply perfect square formula: $\left(a-b\right)^2=a^2-2ab+b^2$

$a=0.5x,\:b=0.6y$

$\left(\sqrt{0.25}x\right)^2-2\cdot \:0.5x\cdot \:0.6y+\left(\sqrt{0.36}y\right)^2=\left(0.5x-0.6y\right)^2$

B) $-a^2+0.6a-0.09$

Multiply both sides by 100

$-a^2\cdot \:100+0.6a\cdot \:100-0.09\cdot \:100\\-100a^2+60a-9$

Factor out common term -1

$-\left(100a^2-60a+9\right)$

Break the expression into groups and factor out common terms

$-(\left(100a^2-30a\right)+\left(-30a+9\right))\\-(10a\left(10a-3\right)-3\left(10a-3\right))\\-(\left(10a-3\right)\left(10a-3\right))\\-\left(10a-3\right)^2$

C) $\frac{9a^4}{16}+a^3+\frac{4a^2}{9}$

Apply exponent rule: $a^{b+c}=a^ba^c$

$a^3=aa^2\\a^4=a^2a^2$

$\frac{9a^2a^2}{16}+aa^2+\frac{4a^2}{9}$

Factor out common term $a^2$

$a^2\left(\frac{9a^2}{16}+a+\frac{4}{9}\right)$

Factor $\frac{9a^2}{16}+a+\frac{4}{9}\right$

Find the Least Common Multiplier (LCM) of 16, 9 which is 144.

Multiply by LCM

$\frac{9a^2}{16}\cdot \:144+a\cdot \:144+\frac{4}{9}\cdot \:144\\81a^2+144a+64$

$81a^2+144a+64=\left(9a\right)^2+2\cdot \:9a\cdot \:8+8^2$

Apply perfect square formula: $\left(a+b\right)^2=a^2+2ab+b^2$

$a=9a,\:b=8$

$81a^2+144a+64=\left(9a+8\right)^2$

$\frac{9a^4}{16}+a^3+\frac{4a^2}{9}=a^2(\left(9a+8\right)^2)$

D) $-16m^2-24mn -9n^2$

Factor out common term -1

$-\left(16m^2+24mn+9n^2\right)$

Break the expression into groups and factor out common terms

$\left(16m^2+12mn\right)+\left(12mn+9n^2\right)\\4m\left(4m+3n\right)+3n\left(4m+3n\right)\\\left(4m+3n\right)\left(4m+3n\right)\\-\left(4m+3n\right)\left(4m+3n\right)\\-\left(4m+3n\right)^2$

$-16m^2-24mn -9n^2=-\left(4m+3n\right)^2$

3 0

4 years ago

Find missing number sequence 1,2,5,10,13,__,__,58,61

Find missing number sequence 1,2,5,10,13,,,58,61