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astraxan [27]
2 years ago
14

Sometimes conflict can be healthy critically discuss this statement brainly.

SAT
1 answer:
vodomira [7]2 years ago
8 0
Conflict is a predictable part of virtually all relationships. It can also be a significant source of stress. Therefore, with most conflicts, it’s important to find a resolution. This seems like a statement of the obvious, but many people suppress their anger or just ‘go along to get along.' They think that by addressing a conflict, they are creating one, and simply keep quiet when upset. Unfortunately, this isn’t a healthy long-term strategy. For one thing, unresolved conflict can lead to resentment and additional unresolved conflict in the relationship. Even more important, ongoing conflict can actually have a negative impact on your health and longevity. (See this piece for more on the detrimental effects of relationship conflict.)​
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Who beat week 7 im still on stress
svetlana [45]

Answer:

Explanation:

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4 0
2 years ago
Read 2 more answers
For how many integers $n$ does the inequality $x^2 + nx + 15 < 0$ have no real solutions $x$?.
Rom4ik [11]

By making the determinant equal to or smaller than zero, we will see that there are 15 values of n such that the inequality has no real solution.

<h3>Solving the inequality:</h3>

Here we have the inequality:

x^2 + n*x + 15 < 0

We want to see for which values of n we don't have real solutions.

Now, we can write the quadratic equation:

y = x^2 + nx + 15.

If the determinant of this quadratic equation is negative or 0, then we have a single root or we don't have roots, and because the leading coefficient is positive, that would mean that the function never becomes negative. Then for these cases, the inequality has no real solutions.

Then we must have:

n^2 - 4*15*1  ≤ 0

Now we can solve this for n.

n^2 ≤ 60

Then if n^2  is smaller than 60, we don't have real solutions, and we know that:

√60 = 7.75

Then we have:

-7.75 ≤ n ≤ 7.75

But n can only be an integer, so we can write:

-7  ≤ n ≤ 7

From -7 to 7 there are 15 integers, then there are 15 values of n such that the inequality has no real solutions.

If you want to learn more about inequalities, you can read:

brainly.com/question/11234618

3 0
1 year ago
How does the poster most likely demonstrate the use of the testimonial technique? the photograph shows fictional film characters
AlexFokin [52]

Answer:

The answer is "The photograph shows fictional film characters, used to 'sell' immunization."

Explanation:

your welcome

7 0
2 years ago
Mathematics course 3 common core 2013 edition solutions
aivan3 [116]
What do you mean? like the entire book??
4 0
2 years ago
37 cos(x2) dx 0 Do the following. (a) Find the approximations T8 and M8 for the given integral. (Round your answer to six decima
dusya [7]

The approximations T8 and M8 for the given integral are:

  • T8 = 33.386321; and
  • M8 = 33.50794

<h3>What is an integral?</h3>

An Integral is a variable of which a given function is the derivative, i.e. it gives that function when differentiated and may express the area under the curve of the function's graph.

<h3>What is the explanation to above answer?</h3>

Given:

F(x) = 37 cox (x²)

Internal = [0,1] n = 8 in Δ x = 1/8

The sub intervals are:

[0, 1/8], [1/8, 2/8], [2/8, 3/8], [ 3/8, 4/8], [ 4/8, 5/8], [ 5/8, 6/8], [6/8, 7/8], [ 7/8, 1]

The mid points are given as:

1/16, 3/16, 5/16, 7/16, 9/16, 11/16, 13/16, 15/16

and X₀ = 0, X₁ = 1/8, X₂ = 2/8

Using the Trapezium Rule which states that:

\int\limits^1_0 cos(x)^{2} } \, dx = Δx/2 [f(xo) + 2f(x1) 2f(x2) + ....+ 2f(x7) + f(x8)]

= 1/1Q[f(0) + 2f (1/8) + 2f(2/8) + ....+ 2f(7/8) + f(1)]

= 0.902333

Now

T8 = \int\limits^1_0 {37Cos(x)^{2} } \, dx

= 37\int\limits^1_0 {(0.902333)} } \, dx

= 37 (0.902333)

T8 = 33.386321

It is to be noted that the midpoints rule is given as;

\int\limits^1_0 {Cos(x)^{2} } \, dx  = Δx [f(1/16) + (3/16) + .... + f(15/16)]

= 1/8[f(1/16) + f (3/16) + f(5/16) + f(7/16) + f(9/16) + f(11/16) + f(13/16) + f(15/16)]

= 0.905620

From the above,

M8 = \int\limits^1_0 {37 Cos(x)^{2} } \, dx

= 37\int\limits^1_0 {Cos(x)^{2} } \, dx

= 37 (0.905620)

M8 = 33.50794

Learn more about integral at;
brainly.com/question/19053586
#SPJ1

6 0
2 years ago
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