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2 years ago

Find the midpoint between two points on a coordinate plane whose coordinates are (5.7) and (-3, 1).

Mathematics

1 answer:

jok3333 [9.3K]2 years ago

6 0

Answer:

(1,4)

Step-by-step explanation:

$if~(x,y)~is~mid~point~of~(x_{1},y_{1})~and~ (x_{2},y_{2}~then\\x=\frac{x_{1}+x_{2}}{2} \\y=\frac{y_{1}+y_{2}}{2} \\x=\frac{5-3}{2} =\frac{2}{2}=1\\y=\frac{7+1}{2} =\frac{8}{2} =4$

(x,y)→(1,4)

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There are 575 fireworks to be shot off in a firework display every minute 12 new fireworks are shot off display write a verbal m

lukranit [14]

Complete question :

There are 575 fireworks to be shot off in a firework display every minute 12 new fireworks are shot off display write a verbal model and algebraic expression to represent the number of fireworks left to be shot off after t minutes.

Answer:

575 - 12t

Step-by-step explanation:

Given the following :

Total number of fireworks = 575

Number of shots per minute = 12

To calculate the number of fireworks left to be shot off after t minutes, The total number of fireworks already shot after the same time interval t in minutes, is first obtained, this is equivalent to (12*t). The result is then subtracted from the total number of fireworks to be shof off.

In algebraic terms

[total number of fireworks on display - (number of shots per minute × t)]

575 - 12t

8 0

3 years ago

Help please!<br><br> How do I graph f(x)=3/4x+2? What points do I plot?

mariarad [96]

(0, 2 ), (4,5)

to draw a graph of a straight line , we only require 2 points

select any 2 values for x, substitute them into the equation for the corresponding y- coordinates

x = 0 → y = 0+2 = 2 ⇒ (0, 2)

x = 4 → y = 3+2 = 5 ⇒ (4, 5)

Plot these 2 points and draw a straight line through them for graph

8 0

3 years ago

Read 2 more answers

[30 POINTS] Please help!!!

Len [333]

Answer:

Part 1) $y=1.5x+5$

Part 2) $y=-(2/3)x-(11/3)$

Part 3) $y=0.25x+2.75$

Part 4) $y=-2x+5$

Part 5) $y=0.5x-1$

Part 6) The graph in the attached figure

Step-by-step explanation:

Part 1) we have

$m=3/2=1.5$

$point(-2,2)$

The equation of the line into point slope form is equal to

$y-y1=m(x-x1)$

substitute

$y-2=1.5(x+2)$

$y=1.5x+3+2$

$y=1.5x+5$

Part 2) we know that

If two lines are perpendicular

then

the product of their slopes is equal to minus one

$m1*m2=-1$

the slope of the line 1 is equal to

$m1=1.5$

Find the slope m2

$1.5*m2=-1$

$m2=-2/3$

Find the equation of the line 2

we have

$m2=-2/3$

$point(-7,1)$

The equation of the line into point slope form is equal to

$y-y1=m(x-x1)$

substitute

$y-1=(-2/3)(x+7)$

$y=-(2/3)x-(14/3)+1$

$y=-(2/3)x-(11/3)$

Part 3) we have

$m=1/4=0.25$

$point(1,3)$

The equation of the line into point slope form is equal to

$y-y1=m(x-x1)$

substitute

$y-3=0.25(x-1)$

$y=0.25x-0.25+3$

$y=0.25x+2.75$

Part 4) we have

$m=-2$

$b=5$ -----> y-intercept

we know that

The equation of the line into slope intercept form is equal to

$y=mx+b$

substitute the values

$y=-2x+5$

Part 5) we have that

The slope of the line 4 is equal to $-2$

the slope of the line perpendicular to the line 4 is equal to

$-2*m=-1\\m=(1/2)=0.5$

therefore

in this problem we have

$m=0.5$

$point(-2,-2)$

The equation of the line into point slope form is equal to

$y-y1=m(x-x1)$

substitute

$y+2=0.5(x+2)$

$y=0.5x+1-2$

$y=0.5x-1$

Part 6)

using a graphing tool

see the attached figure

3 0

3 years ago

9. A line passes through (2, –1) and (8, 4). a. Write an equation for the line in point-slope form. b. Rewrite the equation in s

babunello [35]

Answer:

Step-by-step explanation:

(4+1)/(8-2)= 5/6

y + 1 = 5/6(x - 2)

y + 1 = 5/6x - 5/3

y + 3/3 = 5/6x - 5/3

y = 5/6x - 8/3

6(y = 5/6x - 8/3)

6y = 5x - 16

-5x + 6y = -16

8 0

3 years ago

HELP ME!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!

Bezzdna [24]

The answer is option C. 9xy sqrt 2x

5 0

3 years ago