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Irina-Kira [14]

2 years ago

8

Find the midpoint between two points on a coordinate plane whose coordinates are (5.7) and (-3, 1).

1 answer:

jok3333 [9.3K]2 years ago

6 0

Answer:

(1,4)

Step-by-step explanation:

$if~(x,y)~is~mid~point~of~(x_{1},y_{1})~and~ (x_{2},y_{2}~then\\x=\frac{x_{1}+x_{2}}{2} \\y=\frac{y_{1}+y_{2}}{2} \\x=\frac{5-3}{2} =\frac{2}{2}=1\\y=\frac{7+1}{2} =\frac{8}{2} =4$

(x,y)→(1,4)

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swat32

Answer:

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Step-by-step explanation:

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3 years ago

Enter the domain and range of the function g(x) = 9x2 − 5 as an inequality, using set notation and using interval notation. Comp

tia_tia [17]

The domain and the range of a function are the set of input and output values, the function can take.

<em>The domain and the range of </em> $g(x) = 9x^2 - 2$ <em> is </em> $(-\infty, \infty)$ <em>.</em>
<em>The parent function </em> $f(x) =x^2$ <em> is vertically compressed by 9, then shifted down by 5 units to get </em> $g(x) = 9x^2 - 2$ <em />

<em />

Given

$g(x) = 9x^2 - 2$

<u>Domain and range</u>

There is no restriction as to the input and the output of function g(x).

This means that the domain and the range are $(-\infty, \infty)$

$(-\infty, \infty)$ is in interval notation

The corresponding set notation is: $- \infty < x < \infty$

<u />

<u>The parent function</u>

We have:

$f(x) = x^2$

First, the parent function is vertically compressed by a factor of 9.

The rule of this transformation is:

$(x,y) \to (x,9y)$

So, we have:

$f'(x) = 9x^2$

Next, the function is shifted down by 5 units.

So, we have:

$g(x) = f'(x) - 5$

$g(x) = 9x^2 - 5$

Read more about functions at:

brainly.com/question/21027387

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Answer:

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Answer:

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3 years ago