Answer:
Step-by-step explanation:
a). Given a parametric equation, we are describing a set of coordinates based on the value of t. The variable t is called the parameter.
b) we have the following equations. x=t y=t^2, so in order for us to know where the object is at t=t' we must replace t with the specific value t'. Hence, when t=0 the object is at (0,0^2) = (0,0) (the origin). When t=6, the object is at (6,6^2) = (6,36).
c). To eliminate the parameter, we replace the parameter in one equation by using the second equation. Recall that we have that x=t. Then, by replacing in the second equation, we have the following

where 
Formula for circumference of circle:
C=2πr
here radius, r=4 cm and π=3.142
Put values in formula.
C=2(3.142)(4)
C=25.1 cm (Rounded to 1 decimal place)
Answer: Circumference of the circle is 25.1 cm (Rounded to 1 decimal place)
I think the answer is 14 6/3
Coefficients are 2 and 3
Constant is M