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Llana [10]
2 years ago
13

Can someone please help

Mathematics
1 answer:
Gnoma [55]2 years ago
3 0

Answer: 2, 2, 3

Frequency refers to the number of times an event or value occurs, and in this case, the frequency of the Temperature is the amount of times a number appears in the data.

A grouped frequency table is a frequency table with data organised into smaller groups, often referred to as sets or classes. They can be very useful when we are working with large data sets.

From 101-106 the frequency is 2, because in the data, 104 and 104 fits into the class

From 107-112, the answer is 2, because in the data box to the left, there are two numbers ( 112, 107) that fit into class

From 113-118, you should write the frequency as 3, because the numbers to the left ( 114, 117, 118) fit into the data set.

I hope I explained everything you don't understand! :)

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A manufacturer inspects 500 personal video players and finds that 296 of them have no defects. the manufacturer sent a shipment
snow_tiger [21]
3351/500 = 6.702
296 times 6.702 is 1983.79
Answer is 1984
7 0
3 years ago
A crystallographer measures the horizontal spacing between molecules in a crystal. The spacing is 14.8 nm . What is the total wi
IrinaK [193]
Answer: 1539.2nm

The space between molecule is going as X-1 function. That mean 1 molecule doesn't have space, 2 molecules have 1 space, 3 molecules have 2 space. Then 105 molecules will be will have 104 space.
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4 0
3 years ago
Someone help me quickly plzzz
Black_prince [1.1K]

Answer:

what is the question I don't see it

4 0
3 years ago
Read 2 more answers
in a recent semester at a local university 520 students enrolled in both general chemistry and calculus 1. Of these students 88
IceJOKER [234]

Let Ch and C denote the events of a student receiving an A in <u>ch</u>emistry or <u>c</u>alculus, respectively. We're given that

P(Ch) = 88/520

P(C) = 76/520

P(Ch and C) = 31/520

and we want to find P(Ch or C).

Using the inclusion/exclusion principle, we have

P(Ch or C) = P(Ch) + P(C) - P(Ch and C)

P(Ch or C) = 88/520 + 76/520 - 31/520

P(Ch or C) = 133/520

6 0
3 years ago
Im confused..I feel as if what I’m learning in class itself is not as difficult as the problems my teacher gives us to take home
RideAnS [48]
Ok, so remember that the derivitive of the position function is the velocty function and the derivitive of the velocity function is the accceleration function

x(t) is the positon function
so just take the derivitive of 3t/π +cos(t) twice
first derivitive is 3/π-sin(t)
2nd derivitive is -cos(t)
a(t)=-cos(t)

on the interval [π/2,5π/2) where does -cos(t)=1? or where does cos(t)=-1?
at t=π
so now plug that in for t in the position function to find the position at time t=π
x(π)=3(π)/π+cos(π)
x(π)=3-1
x(π)=2
so the position is 2







ok, that graph is the first derivitive of f(x)
the function f(x) is increaseing when the slope is positive
it is concave up when the 2nd derivitive of f(x) is positive

we are given f'(x), the derivitive of f(x)
we want to find where it is increasing AND where it is concave down

it is increasing when the derivitive is positive, so just find where the graph is positive (that's about from -2 to 4)

it is concave down when the second derivitive (aka derivitive of the first derivitive aka slope of the first derivitive) is negative
where is the slope negative?
from about x=0 to x=2
and that's in our range of being increasing
so the interval is (0,2)
4 0
3 years ago
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