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vekshin1
3 years ago
15

Factor the equation please help

Mathematics
1 answer:
LiRa [457]3 years ago
8 0

Answer:

<u>For</u><u> </u><u>A</u>

{ \rm{6 {x}^{2}(x + 1) - 2x(x + 1) }}

• The equation above has a common bracket "(x + 1)". So, let's first factorise out that bracket:

\dashrightarrow \: { \rm{(x + 1) \{6 {x}^{2} - 2x \} }}

• now in the second bracket, the common factor is x and 2.

\dashrightarrow \: { \rm{(x + 1) \{2x(3x - 1) \}}}

• Final answer;

{ \boxed{ \boxed{ \rm{ \dashrightarrow \: 2x(x + 1)(3x - 1) \:  \: }}}}

<u>For</u><u> </u><u>B</u>

{  \rm{3(x - 1)(x + 2) + ( {x}^{2} - x)(x + 2) }}

• In the equation, the common bracket is (x + 2).

So let's first factorise it out:

\dashrightarrow \: { \rm{(x + 2) \{3(x - 1) + ( {x}^{2}  - x) \}}} \\  \\ { \rm{(x + 2) \{3(x - 1) + x(x - 1) \}}}

• In the second major bracket, the common bracket is (x - 1). so factorise it out:

{  \rm{(x + 2) (x - 1) \{3 + x \}}}

• Final answer:

{ \boxed{ \boxed{ \rm{ \dashrightarrow \: (x + 2)(x  + 3)(x - 1) \:  \: }}}}

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Help algebra 2 please
34kurt

Answer:

option 4

Step-by-step explanation:

(f*g)(x) =(x² + x+ 1)*(x² - x -1)

           = x²*(x² - x -1)   + x(x² - x -1) + 1*( x² - x -1)

            = x²*x² - x²*x -x²*1   + x*x² - x*x -x*1 + x² - x -1

            = x⁴ - x³ - x² +x³ - x²  - x  + x² - x -1

           = x⁴  - x³ + x³  - x² - x² + x² - x - x - 1

       = x⁴ - x² - 2x - 1

4 0
2 years ago
Read 2 more answers
Two experiments are defined below. An event is defined for each of the experiments. Experiment I: Corrine rolls a standard six-s
-BARSIC- [3]

Answer: The correct answer is option C: Both events are equally likely to occur

Step-by-step explanation: For the first experiment, Corrine has a six-sided die, which means there is a total of six possible outcomes altogether. In her experiment, Corrine rolls a number greater than three. The number of events that satisfies this condition in her experiment are the numbers four, five and six (that is, 3 events). Hence the probability can be calculated as follows;

P(>3) = Number of required outcomes/Number of possible outcomes

P(>3) = 3/6

P(>3) = 1/2 or 0.5

Therefore the probability of rolling a number greater than three is 0.5 or 50%.

For the second experiment, Pablo notes heads on the first flip of a coin and then tails on the second flip. for a coin there are two outcomes in total, so the probability of the coin landing on a head is equal to the probability of the coin landing on a tail. Hence the probability can be calculated as follows;

P(Head) = Number of required outcomes/Number of all possible outcomes

P(Head) = 1/2

P(Head) = 0.5

Therefore the probability of landing on a head is 0.5 or 50%. (Note that the probability of landing on  a tail is equally 0.5 or 50%)

From these results we can conclude that in both experiments , both events are equally likely to occur.

3 0
3 years ago
Find the distance between A (6, -1) and B ( -18, 15)
timama [110]

Answer:

8√13 units

Step-by-step explanation:

We use the distance formula.

The distance formula states that the distance between two points (x, y) and (a, b) is equal to:

d = \sqrt{(x-a)^2+(y-b)^2}

Here, x = 6, y = -1, a = -18, and b = 15. Plug these in:

d = \sqrt{(x-a)^2+(y-b)^2}

d = \sqrt{(6-(-18))^2+(-1-15)^2}=\sqrt{24^2+(-16)^2} =\sqrt{576 + 256} =\sqrt{832} = 8√13

The answer is thus 8√13 units.

<em>~ an aesthetics lover</em>

7 0
3 years ago
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Please help asap 25 pts
beks73 [17]
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I need all three answer for an assignment
AfilCa [17]
This is false... you can get an easy example: (-2) + (10) = 10 - 2 = 8
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3 years ago
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