1 Simplify 1/2x^2 to x^2/2
X^2/2 - x+5=0
2 Use the Quadratic Formula
x=1+3ı,1−3ı
So the answer is the first one a
1) 16x^2-8x+5
2) -2x^3+10x^2+18-6x
Using the Pythagoras theorem since it is given that it is a right angled triangle
let us name the triangle as A, B, C with B as right angle
AB^2 + BC^2 = AC^2 ( Pythagoras theorem)
where AB = 4 , BC = 7 , AC = x
Answer:
where 
Step-by-step explanation:
given equation is:

since no range is provided we can solve for all values of
:


for one cycle of cos 
for all cycles of cos
we should also include negative values.

we can divide each value by 2, to get the solutions for
instead of 
Answer:

This is the solution of the equation
.
In its most general form we can write all solutions of the equation in terms of 
where
or n is an integer.
We can write <em>S</em> as

and expand it as

The first sum is geometric, nothing tricky:

For the second sum, you can use the same method employed in another question of yours (24494877) to find

So this sum comes out to
