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pogonyaev
3 years ago
7

What is the slope of the line below? Give an exact number

Mathematics
2 answers:
Slav-nsk [51]3 years ago
6 0

Answer:

The slope of straight line in the graph is

m = \frac{1}{2}

Step-by-step explanation:

Slope of a given line is m = \frac{y_{2}-y_{1}  }{x_{2} - x_{1} }........(1)

The point (-2,0) lie on x-axis in the graph and another point ( 0, 1) lie on y- axis.

so (x_{1} , y_{1}) = (-2,0)  and (x_{2} , y_{2}) = (0,1)

substitute these values in equation (1)

m = \frac{1-0}{0-(-2)}

m = \frac{1}{2}

slope of given line is m = \frac{1}{2}

Maksim231197 [3]3 years ago
4 0

Answer:

-2 by 1

Step-by-step explanation:

idk

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The Floyds have considered three options to ensure they have at least $1,375 saved for their trip.
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Help please!posted picture of question
Evgen [1.6K]
The region is in the first quadrant, and the axis are continuous lines, then x>=0 and y>=0
The region from x=0 to x=1 is below a dashed line that goes through the points:
P1=(0,2)=(x1,y1)→x1=0, y1=2
P2=(1,3)=(x2,y2)→x2=1, y2=3
We can find the equation of this line using the point-slope equation:
y-y1=m(x-x1)
m=(y2-y1)/(x2-x1)
m=(3-2)/(1-0)
m=1/1
m=1
y-2=1(x-0)
y-2=1(x)
y-2=x
y-2+2=x+2
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The region is below this line, and the line is dashed, then the region from x=0 to x=1 is:
y<x+2 (Options A or B)

The region from x=2 to x=4 is below the line that goes through the points:
P2=(1,3)=(x2,y2)→x2=1, y2=3
P3=(4,0)=(x3,y3)→x3=4, y3=0
We can find the equation of this line using the point-slope equation:
y-y3=m(x-x3)
m=(y3-y2)/(x3-x2)
m=(0-3)/(4-1)
m=(-3)/3
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y-0=-1(x-4)
y=-x+4
The region is below this line, and the line is continuos, then the region from x=1 to x=4 is:
y<=-x+2 (Option B)

Answer: The system of inequalities would produce the region indicated on the graph is Option B

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