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Andreyy89
3 years ago
15

Trigonametry quiz q.8 part A/B

Mathematics
1 answer:
nekit [7.7K]3 years ago
7 0
I think it is cos2/5
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The sum of three consecutive even numbers is 114. what is the smallest of the three numbers?​
saul85 [17]

Answer:

36

Step-by-step explanation:

Let's let n be any number.

If we multiply n by 2, we get 2n. Since anything multiplied by 2 is even, 2n <em>must</em> be even. Therefore, let 2n be our first number.

So, the consecutive even number will be (2n+2) followed by (2n+4).

We know that their sum must be 114. Therefore, we can write the following equation:

(2n)+(2n+2)+(2n+4)=114

Solve for n. Combine like terms on the left:

6n+6=114

Subtract 6 from both sides:

6n=108

Finally, divide both sides by 6. Therefore, the value of n is:

n=108/6=18

Therefore, our first even number is 2n or 2(18) which equates to 36.

And the consecutive even numbers will be 38 and 40.

So, the smallest of them, the first term, is 36.

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Each cube in this solid figure is a unit cube.
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picture unclear         because it is to find the sum of consecutive numbers 1 to 100, you multiply the number of sets (50) by the sum of each set (101): 101(50)=5050.{\displaystyle 101(50)=5050.} So, the sum of consecutive number 1 through 100 is 5,050 .

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Just fail it.

Step-by-step explanation:

Sleep in class

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Get put into e2020 and get ALL the answers off of here.

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Answer:

that is the correct answer

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