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3 years ago

Find the inequality of the graph, please help

Mathematics

1 answer:

vodomira [7]3 years ago

4 0

The gradient of the line is 2.5, the y-intercept is 5.

The equation representing the line is y = 2.5x + 5

Based on the concept mentioned in my previous answers to your questions, this means the shaded region is represented by y ≤ 2.5x + 5

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The probability that the parking lot of a mall is full on a holiday is 0.19. The probability that it is a holiday is 0.29. What

Marta_Voda [28]

19 percent, because holiday is given therefore you just take the percentage of the parking lot <span />

8 0

4 years ago

2) If it is 12° outside and the temperature is going to -7° drop 19º. What will the new temperature be?

shutvik [7]

Answer:

69 degrees

Step-by-step explanation:

yeah

3 0

2 years ago

What is the relationship between the degree measure of the angle formed by the straight edges of a section of a circle graph as

Butoxors [25]

Answer:

degree measure = 360° × percent of data

Step-by-step explanation:

The ratio of the degree measure of a sector of a circle graph to 360° is the same as the ratio of the represented data to the whole amount of data.

The idea of a circle graph is that the area of the sector is proportional to the data being represented. That is, if the data represented is 10% of the whole, then the sector area is 10% of the whole. Sector area is proportional to the degree measure of its central angle, so the example sector would have a central angle of 10% of 360°, or 36°.

The ratio of the central angle of the sector to 360° is the same as the percentage of data that sector represents.

7 0

3 years ago

Please help me with this question. Thanks!

olasank [31]

Assuming that all the grapes have the same probability of being randomly picked:

a) 0.11
b) 0.24

<h3>How to find the probabilities?</h3>

We know that there are 8 green grapes and 15 red grapes on the bowl, so there is a total of 23 grapes.

a) Here we need to find the probability that both grapes are green. Remember that the probability of getting a green grape is equal to the quotient between the number of green grapes and the total number of grapes, this is:

P = 8/23

But then he must take another, because he already took one, the number of green grapes is 7, and the total number of grapes is 22, so for the second grape the probability is:

P' = 7/22.

The joint probability is the product of the two individual probabilities:

prob = (8/23)*(7/22) = 0.11

b) For the first green grape we know that the probability is:

P = 8/23

Then he must get a red grape. There are 15 red grapes and 22 grapes in total, so the probability is:

P' = 15/22

Then the joint probability is:

prob = (8/23)*(15/22) = 0.24

If you want to learn more about probability:

brainly.com/question/25870256

#SPJ1

8 0

3 years ago

Find the laplace transform of f(t) = cosh kt = (e kt + e −kt)/2

iren2701 [21]

Hello there, hope I can help!

I assume you mean $L\left\{\frac{ekt+e-kt}{2}\right\}$
With that, let's begin

$\frac{ekt+e-kt}{2}=\frac{ekt}{2}+\frac{e}{2}-\frac{kt}{2} \ \textgreater \ L\left\{\frac{ekt}{2}-\frac{kt}{2}+\frac{e}{2}\right\}$

$\mathrm{Use\:the\:linearity\:property\:of\:Laplace\:Transform}$
$\mathrm{For\:functions\:}f\left(t\right),\:g\left(t\right)\mathrm{\:and\:constants\:}a,\:b$
$L\left\{a\cdot f\left(t\right)+b\cdot g\left(t\right)\right\}=a\cdot L\left\{f\left(t\right)\right\}+b\cdot L\left\{g\left(t\right)\right\}$
$\frac{ek}{2}L\left\{t\right\}+L\left\{\frac{e}{2}\right\}-\frac{k}{2}L\left\{t\right\}$

$L\left\{t\right\} \ \textgreater \ \mathrm{Use\:Laplace\:Transform\:table}: \:L\left\{t\right\}=\frac{1}{s^2} \ \textgreater \ L\left\{t\right\}=\frac{1}{s^2}$

$L\left\{\frac{e}{2}\right\} \ \textgreater \ \mathrm{Use\:Laplace\:Transform\:table}: \:L\left\{a\right\}=\frac{a}{s} \ \textgreater \ L\left\{\frac{e}{2}\right\}=\frac{\frac{e}{2}}{s} \ \textgreater \ \frac{e}{2s}$

$\frac{ek}{2}\cdot \frac{1}{s^2}+\frac{e}{2s}-\frac{k}{2}\cdot \frac{1}{s^2}$

$\frac{ek}{2}\cdot \frac{1}{s^2} \ \textgreater \ \mathrm{Multiply\:fractions}: \frac{a}{b}\cdot \frac{c}{d}=\frac{a\:\cdot \:c}{b\:\cdot \:d} \ \textgreater \ \frac{ek\cdot \:1}{2s^2} \ \textgreater \ \mathrm{Apply\:rule}\:1\cdot \:a=a$
$\frac{ek}{2s^2}$

$\frac{k}{2}\cdot \frac{1}{s^2} \ \textgreater \ \mathrm{Multiply\:fractions}: \frac{a}{b}\cdot \frac{c}{d}=\frac{a\:\cdot \:c}{b\:\cdot \:d} \ \textgreater \ \frac{k\cdot \:1}{2s^2} \ \textgreater \ \mathrm{Apply\:rule}\:1\cdot \:a=a$
$\frac{k}{2s^2}$

$\frac{ek}{2s^2}+\frac{e}{2s}-\frac{k}{2s^2}$

Hope this helps!

3 0

4 years ago