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2 years ago

Triangle mid-segment ???

Mathematics

1 answer:

adoni [48]2 years ago

8 0

Answer:

Step-by-step explanation:

The midsegment is always half as long as the base, so

2(6 + 4x) = 5x + 24

12 + 8x = 5x + 24

3x = 12

x = 4

Replace the 4 in for x,

6 + 4(4) = 22

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14. Suppose that 1 out of every 10,000 doctors in a certain region is infected with the SARS virus; in the same region, 20 out o

hram777 [196]

Answer:

The person in the at-risk population is much more likely to actually have the disease

Step-by-step explanation:

The probability of a randomly selected doctor having the disease is 1 in 1,000 (P(I)=0.0001).

The probability that a doctor is infected with SARS, given that they tested positive is:

$P(I|+)=\frac{P(I)*0.99}{P(I)*0.99+(1-P(I))*0.01}\\P(I|+)=\frac{0.0001*0.99}{0.0001*0.99+(1-0.0001)*0.01}\\P(I|+)=9.9*10^{-3}$

The probability of a randomly selected person from the at-risk population having the disease is 20 in 100 (P(I)=0.20).

The probability that a person in the at-risk population is infected with SARS, given that they tested positive is:

$P(I|+)=\frac{P(I)*0.99}{P(I)*0.99+(1-P(I))*0.01}\\P(I|+)=\frac{0.2*0.99}{0.2*0.99+(1-0.2)*0.01}\\P(I|+)=0.962$

Therefore, the person in the at-risk population is much more likely to actually have the disease

3 0

3 years ago

HELP PLEASE !!! Place each expression under the equivalent expression in the table.

tino4ka555 [31]

Answer:

Option 3,5 are under first expression and Option 1,2 are under second expression.

Step-by-step explanation:

1). $\frac{(x-4)(x+2)}{x^{2}+5x+6}+\frac{-3x^{2}+24x-20}{(x+3)(4x-5)}$

$=\frac{(x-4)(x+2)}{(x+3)(x+2)}+\frac{-3x^{2}+24x-20}{(x+3)(4x-5)}$ $=\frac{(x-4)}{(x+3)}+\frac{-3x^{2}+24x-20}{(x+3)(4x-5)}$

$=\frac{(x-4)(4x-5)-3x^{2}+24x-20}{(x+3)(4x-5)}$

$=\frac{4x^{2}-5x-16x+20-3x^{2}+24x-20}{(x+3)(4x-5)}$ $=\frac{x^{2}+3x}{(x+3)(4x-5)}$

$=\frac{x(x+3)}{(x+3)(4x-5)}=\frac{x}{4x-5}$

2). $\frac{3x}{4x-5}-\frac{4x^{2}}{8x^{2}-10x}=\frac{3x}{4x-5}-\frac{4x}{8x-10}$ $=\frac{3x(8x-10)-4x(4x-5)}{(4x-5)(8x-10)}$

$=\frac{24x^{2}-30x-16x^{2}+20x}{(4x-5)(8x-10)}$

$=\frac{8x^{2}-10x}{(4x-5)(8x-10)}$ $=\frac{x(8x-10)}{(4x-5)(8x-10)}=\frac{x}{4x-5}$

3). $\frac{6x^{2}}{x^{2}-7x+10}\div \frac{2x}{x-5}$

$=\frac{6x^{2}}{x^{2}-7x+10}\times \frac{x-5}{2x}$

$=\frac{3x(x-5)}{x^{2}-7x+10}$

$=\frac{3x(x-5)}{(x-5)(x-2)}=\frac{3x}{x-2}$

4). $\frac{-x}{4x-5}-\frac{4x^{2}}{16x^{2}-22x}$

$=\frac{-x}{4x-5}-\frac{2x}{8x-11}$

$=\frac{-x(8x-11)-2x(4x-5)}{(4x-5)(8x-11)}$

$=\frac{-8x^{2}+11x-8x^{2}+10x}{(4x-5)(8x-11)}$

$=\frac{-16x^{2}+21x}{(4x-5)(8x-11)}=\frac{-x(16x-21)}{(4x-5)(8x-11)}$

5). $\frac{3x^{2}}{x+3}\times \frac{2(x+3)}{2x^{2}-4x}$

$=\frac{6x^{2}(x+3)}{2x(x+3)(x-2)}=\frac{3x}{x-2}$

6). $\frac{5x^{2}}{x-2}\times \frac{2x+6}{8x^{2}-4x}$

$=\frac{10x^{2}(x+3)}{4x(x-2)(2x-1)}$

4 0

3 years ago

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PLEASE HeLp!!!!<br> Question BELow!

Law Incorporation [45]

I'm going to label them from top to bottom 1,2,3,4,5
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8 0

4 years ago

What two factors multiply to -60 and adds up to 11

pychu [463]

-60 is negative so the 2 facotrs are different signs
11 is positive so therefor te positive factor is bigger than negative

list all factors and add and find which add to 11
60-1=59 nope
30-2=28 nope
20-3=17 nope
15-4=11 yep

factors are 15 and -4

4 0

3 years ago

HELP I WILL GIVE 50 POINTS AND BRAINLIEST TO WHOEVER ANSWERS FIRST Graph y>1−3x.

AleksandrR [38]

Answer:

The last graph

Step-by-step explanation:

This is because when there is a greater than sign, the line on the graph is dotted and the shaded area is facing upwards. I try to remember that when there is a greater than sign or a greater than or equal to sign, the shaded area faces up towards the sky.

Hope this helps. Please inform me if my answer is wrong.

7 0

3 years ago

Read 2 more answers