Answer:
13. it says nearest whole number.
Step-by-step explanation:
Answer:
y=1x-6
Step-by-step explanation:
luckily i love math, plz put as brainliest
Answer:
11.75 years
Step-by-step explanation:
If we ignore the fact that "6-sigma" quality means the error rate corresponds to about -4.5σ (3.4 ppm) and simply go with ...
P(z ≤ -6) ≈ 9.86588×10^-10
and
P(z ≤ -4.5) ≈ 3.39767×10^-6
the ratio of these error rates is about 0.000290372. We're multiplying the error rate by 0.5 each year, so we want to find the power of 0.50 that gives this value:
0.50^t = 0.000290372
t·log(0.50) = log(0.00290372) . . . . take logarithms
t = log(0.000290372)/log(0.50) ≈ -3.537045/-0.301030
t ≈ 11.75
It will take about 11.75 years to achieve Six Sigma quality (0.99 ppb error rate).
_____
<em>Comment on Six Sigma</em>
A 3.4 ppm error rate is customarily associated with "Six Sigma" quality. It assumes that the process may have an offset from the mean of up to 1.5 sigma, so the "six sigma" error rate is P(z ≤ (1.5 -6)) = P(z ≤ -4.5) ≈ 3.4·10^-6.
Using that same criteria for the "4.5-Sigma" quality level, we find that error rate to be P(z ≤ (1.5 -4.5)) = P(z ≤ -3) ≈ 1.35·10^-3.
Then the improvement ratio needs to be only 0.00251699, and it will take only about ...
t ≈ log(0.00251699)/log(0.5) ≈ 8.6 . . . . years
Answer:
2. Tom ran from his house to the bus stop and waited. He realised that he missed the bus so he walked home
Step-by-step explanation:
He ran to the bus stop so his distance from his home is far, then he waited so the distance did not change, and then he went back home so the distance to the house got smaller again.
Answer:
0.7486 = 74.86% observations would be less than 5.79
Step-by-step explanation:
I suppose there was a small typing mistake, so i am going to use the distribution as N (5.43,0.54)
Problems of normally distributed samples can be solved using the z-score formula.
In a set with mean
and standard deviation
, the zscore of a measure X is given by:

The Z-score measures how many standard deviations the measure is from the mean. After finding the Z-score, we look at the z-score table and find the p-value associated with this z-score. This p-value is the probability that the value of the measure is smaller than X, that is, the percentile of X. Subtracting 1 by the pvalue, we get the probability that the value of the measure is greater than X.
The general format of the normal distribution is:
N(mean, standard deviation)
Which means that:

What proportion of observations would be less than 5.79?
This is the pvalue of Z when X = 5.79. So



has a pvalue of 0.7486
0.7486 = 74.86% observations would be less than 5.79