What was his average speed rate on his way to Seattle?
Ans: 62mph
On which part of his trip did he average a faster speed rate?
Ans: When he returned home.
The solution to the problem is as follows:
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the genaral term is 5Cr(-1)^r 2^r x^(5-2r)
and so need 5-2r = -1 => r = 3
Coeff is then 5C3 (-1)^3 2^3 = -80
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Answer:
A) x = (-8log(6)-2log(17))/(-2log(17)+log(6))
Step-by-step explanation:
Taking the logarithm of the equation, you have ...
(x+8)log(6) = (2x-2)log(17)
Subtracting the right side from the equation gives ...
x(log(6) -2log(17)) +8log(6)+2log(17) = 0
Subtracting the constant and dividing by the coefficient of x gives ...
x = -(8log(6) +2log(17))/(log(6) -2log(17)) . . . . . matches selection A
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You don't need to work out the whole solution to determine the correct answer choice. Once you take the initial log, you find that the x-coefficient includes a multiplier of 2log(17). This term only appears in the denominator of choice A. (The value of x will be found after dividing by the x-coefficient, so you know this must show up in the denominator of the answer.)
Isolate k by dividing both sides by 8
8k=4/9
k=4/72
Reduce if possible
4/72 -> 1/18
Step-by-step explanation:
y=|x| is a vee graph starting at (0,0)
y=|x| - 3 is a vee graph starting (0,-3)
see attachment
