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ss7ja [257]
2 years ago
5

Jimmy has a window frame in his house. The window measures to have a width of 36 inches and a height of 48 inches. What is the d

iagonal distance of the window in Jimmy's house?
A. 84 inches

B.60 inches

C.9 inches

D.32 inches
Mathematics
1 answer:
Olenka [21]2 years ago
4 0

Answer:

B.60 inches

Step-by-step explanation:

you know you can consider two triangles because of the diagonal cut. and the distance wound be √(36²+48²)=60 inches

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Using PYTHAGORAS THEOREM answer the question A vertical pillar ab bent at c at a height of 2.4m and its upper end b touches the
Alisiya [41]

Answer:

  5.4 m

Step-by-step explanation:

The Pythagorean theorem tells you the relationship between the various lengths is ...

  cd² = ac² +ad²

  cd² = (2.4 m)² + (1.8 m)² = 9.00 m²

  cd = √(9.00 m²) = 3.0 m

Since cd = cb and ab = ac+cb, we have ...

  ab = 2.4 m + 3.0 m = 5.4 m

_____

You may recognize this as a 3-4-5 right triangle with a scale factor of 0.6. We are asked for the sum of the lengths of the "4" and "5" legs, which is ...

  0.6·(4+5) = 5.4

7 0
3 years ago
How do I solve |5-3p|+9=13p+8
anastassius [24]

Answer:

p = -2/5 or 3/8

Step-by-step explanation:

|5 − 3p| + 9 = 13p + 8

|5 − 3p| = 13p − 1

If 5 − 3p is positive:

5 − 3p = 13p − 1

6 = 16p

p = 3/8

If 5 − 3p is negative:

-(5 − 3p) = 13p − 1

-5 + 3p = 13p − 1

-4 = 10p

p = -2/5

Alternatively, we can square both sides of the equation:

(5 − 3p)² = (13p − 1)²

25 − 30p + 9p² = 169p² − 26p + 1

0 = 160p² + 4p − 24

0 = 40p² + p − 6

0 = (5p + 2) (8p − 3)

p = -2/5 or 3/8

8 0
3 years ago
Please help!! I don't know what to do :(
elena55 [62]

Yo sup??

This question can be solved by applying the properties of similar triangles

the triangle with sides 5x and 20 is similar to the triangle with sides 45 and 36

therefore we can say

5x/45=20/36

x=5 units

Hope this helps

8 0
3 years ago
Solve for n: 3n + 2 – n = -4
Sav [38]
The value of x is -3, or x= -3
6 0
3 years ago
Lots of points:
Makovka662 [10]
480 + 192 = 672 students total
16 + 12 = 28 classrooms total
672/28 = 24 students per room
24 * 12 = 288 students that need to be in school B
288 - 192 = 96 students who have to transfer
5 0
3 years ago
Read 2 more answers
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