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2 years ago

A book with 650 pages has 3 pages with diagrams.

Mathematics

1 answer:

Tems11 [23]2 years ago

4 0

Answer:

0.46% is the answer sorry for being late

Step-by-step explanation:

took the test :D hope this helps

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20 POINTS AND BRAINLIEST

emmainna [20.7K]

To solve this equation we must first plug in 5 for x.

$\frac{1}{3}$ <span> (5 - 4x)
</span>↓
$\frac{1}{3}$ (5 - 4 · 5)

The next step would be to multiply 4 by 5 to get rid of the parenthesis within our main parenthesis.

$\frac{1}{3}$ (5 - 4 · 5)

$\frac{1}{3}$ (5 - 20)

The next step would be to subtract both of the numbers within the parenthesis.

$\frac{1}{3}$ (-15)

Now we must multiply.

- $\frac{1}{3}$ · 15 = - $\frac{1×15}{3}$

- $\frac{15}{3}$

Now we simplify our answer to get our final answer.

-5

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3 years ago

A bakery sells 5 apple muffins for every 2 bran muffins sold. which table shows this ratio?

shepuryov [24]

The answer to this question is the graph B

6 0

3 years ago

Read 2 more answers

Simplity find the quotient and the remainder of (2x2+9x+8)÷(x+2)

Nuetrik [128]

That’s what I got I didn’t know how to type it so I just took a photo

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3 years ago

Please need help don't understand please explain

const2013 [10]

Answer:

Combine like terms for the than you do to other side the multiply last for least you divide both sides

Step-by-step explanation:

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2 years ago

Graph the hyperbola using the transverse axis, vertices, and co-vertices:

Reptile [31]

See attachment for the graph of the hyperbola 12x^2 - 3y^2 - 108 = 0

<h3>How to graph the hyperbola?</h3>

The equation of the hyperbola is given as:

12x^2 - 3y^2 - 108 = 0

Start by calculating the transverse axis

So, we have:

<u>Transverse axis</u>

The vertices of the given hyperbola are (0, 0)

This means that

(h, k) = 0

Where

a = 3 and b = 6

The transverse axis is calculated as:

y = ±b/a(x - h) + k

So, we have:

y = ±6/3(x - 0) + 0

Evaluate the difference and sum

y = ±6/3x

Evaluate the quotient

y = ±2x

This means that the transverse axes are y = 2x and y =-2x

<u>The vertices</u>

In the above section, we have:

The vertices of the given hyperbola are (0, 0)

This means that

(h, k) = 0

<u>The co-vertices</u>

In the above section, we have:

The vertices of the given hyperbola are (0, 0)

This means that

(h, k) = 0

And

a = 3 and b = 6

The co-vertices are

(h - a, k) and (h + a, k)

So, we have:

(0 - 3, 0) and (0 + 3, 0)

Evaluate

(-3,0) and (3, 0)

See attachment for the graph of the hyperbola