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ziro4ka [17]
2 years ago
14

Please don't leave half an answer for the points!

Mathematics
1 answer:
vovikov84 [41]2 years ago
5 0

Answer:

  1. T . . . labeling shown below
  2. U
  3. R
  4. S

Step-by-step explanation:

Matrix multiplication of A(a rows, b columns) and B(b rows, c columns) will result in a product matrix of AB(a rows, c columns). This fact can be used to reduce the number of candidates for each product.

For the given factor tiles, the resulting product dimensions will be ...

  [2, 3]  [3, 2]  [2, 2]   ⇒  Q, R, S

  [2, 3]  [3, 3]  [3, 2]   ⇒   T, U, V

  [3, 3]   ⇒   W

1. For this 2×3 product, candidates are Q and T. The upper left term for the product in Q is (2)(3) +(1)(7) +(0)(8) = 13. The appropriate choice is T.

2. For this 3×3 product, candidates are U and W. The upper left term for the product in U is 9(2) +1(2) +9(5) +5(1) = 18 +2 +45 +5 = 70. The appropriate choice is U.

3. For this 3×2 product, candidates are R and V. The upper left term for the product in R is 1(4) +2(0) +4(1) = 4 +0 +4 = 8. The appropriate choice is R.

4. For this 2×2 product, there is only one candidate: S.

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According to a study done by a university​ student, the probability a randomly selected individual will not cover his or her mou
VikaD [51]

Complete Question

The complete question is shown on the first uploaded image

Answer:

a

 P(X = 8) =  0.0037

b

 P(X <  5) =  0.805

c

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I would be surprised because the value is very small , less the 0.05

Step-by-step explanation:

From the question we are told that

The probability a randomly selected individual will not cover his or her mouth when sneezing is p = 0.267

Generally data collected from this study follows  binomial  distribution because the number of trials is  finite , there are only two outcomes, (covering  , and  not covering mouth when sneezing ) , the trial are independent

Hence for a randomly selected variable  X we have that  

   X \ \ \~ \ \ { B ( p , n )}

The probability distribution function for binomial  distribution is  

    P(X = x ) =  ^nC_x *  p^x *  (1 -p) ^{n-x}

Considering question a

Generally the  the probability that among 12 randomly observed individuals exactly 8 do not cover their mouth when​ sneezing is mathematically represented as

     P(X = 8) =  ^{12} C_8 *  (0.267)^8 *  (1- 0.267)^{12-8}

Here C denotes  combination

So

     P(X = 8) =  495  *  0.000025828 * 0.28867947

    P(X = 8) =  0.0037

Considering question b

Generally the probability that among 12 randomly observed individuals fewer than 5 do not cover their mouth when​ sneezing is mathematically represented as

     P(X <  5 ) =[P(X = 0 ) + \cdots + P(X = 4)]

=>   P(X <  5 ) =[ ^{12} C_0 *  (0.267)^0 *  (1- 0.267)^{12-0} + \cdots +  ^{12} C_4 *  (0.267)^4 *  (1- 0.267)^{12-4} ]

=> P(X <  5 )  =  0.02406 +  0.10516 + 0.21067 + 0.25580 + 0.20964

=>  P(X <  5) =  0.805

Considering question c

Generally the probability that fewer than half(6) covered their mouth when​ sneezing(i.e the probability the greater than half do not cover their mouth when sneezing) is mathematically represented as

      P(X > 6) =  1 - p(X \le  6)

=>    P(X > 6) = 1 - [P(X = 0) + \cdots + P(X =6)]

=>    P(X > 6)=1 - [^{12} C_0 *  (0.267)^0 *  (1- 0.267)^{12-0}+ \cdots + ^{12} C_4 *  (0.267)^6 *  (1- 0.267)^{12-6} ]

=>    P(X > 6)= 1 - [0.02406 + \cdots + 0.0519 ]  

=>    P(X > 6) =  0.0206

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