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3 years ago

What is 498,235 rounded to the nearest thousands?

Mathematics

1 answer:

babymother [125]3 years ago

6 0

Answer:

498,000

Step-by-step explanation:

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A scientist had 3 1/2 liters of vinegar. He poured 2/3 of the vinegar into beaker. He then used 3/5 of the vinegar in the beaker

valentinak56 [21]

Answer:

A)2100 ml

Step-by-step explanation:

Given total vinegar is 3 1/2 liters and the used vinegar is 3/5 of the vinegar in the beaker:

#First calculate the amount of vinegar not poured in the beaker:

$V_o=V_t-V_b\\\\=3\frac{1}{2}(1-\frac{2}{3})\\\\=1\frac{1}{6}$

#Calculate amount of vinegar used in experiment:

$V_b=\frac{2}{3}V_t=\frac{2}{3}(3\frac{1}{2})=2\frac{1}{3}\\\\V_u=\frac{3}{5}V_b=\frac{3}{5}\times 2\frac{1}{3}=1\frac{2}{5}$

#The unused vinegar is therefore calculated by subtracting the used vinegar from the total at the start of the experiment:

$V_r=V_t-V_u\\\\=3\frac{1}{2}-1\frac{2}5}\\\\=2\frac{1}{10}\times 1000\ ml\\\\=2100\ ml$

Hence, the unused vinegar is 2100 ml

8 0

3 years ago

Can someone pls give me the answer for this?

Mashutka [201]

Answer:

Step-by-step explanation:

5 0

3 years ago

Read 2 more answers

Sections of prefabricated fencing are each 4 1/3 feet long how long are 6 1/2 sections placed end to end

vovangra [49]

I hope this helps you

8 0

3 years ago

If f(x) = 8x2 − x3, find f'(2) and use it to find an equation of the tangent line to the curve y = 8x2 − x3 at the point (2, 24)

Ymorist [56]

Take derivitive to find slope
$f'(x)=16x-3x^2$

at x=2
$f'(2)=16(2)-3(2)^2$
$f'(2)=32-3(4)$
$f'(2)=32-12$
$f'(2)=20$

so the slope of f(x) at the point (2,24) is 20

use point slope form
the equation of a line that passes through the point $(x_1,y_1)$ and has a slope of m is
$y-y_1=m(x-x_1)$
we are given that the slope is 20 and the point is (2,24)

the equation is
$y-24=20(x-2)$
simplify into different form yourself if needed

3 0

3 years ago

<img src="https://tex.z-dn.net/?f=y%20%3D%20%20%5Cfrac%7B%20%20%5Csqrt%7B3x%7D%20%7D%7B1%20%2B%20e%5E%7B2x%7D%20%7D%20" id="TexF

kumpel [21]

$~~~~~~~~y = \dfrac{\sqrt{3x}}{ 1+ e^{2x}}\\\\\\\implies \dfrac{dy}{dx} = \dfrac{d}{dx} \left( \dfrac{\sqrt{3x}}{1+ e^{2x}} \right)\\\\\\~~~~~~~~~~~~=\dfrac{(1 + e^{2x} ) \dfrac{d}{dx} \left(\sqrt{3x} \right) - \left(\sqrt{3x} \right)\dfrac{d}{dx}(1+e^{2x})}{\left( 1+ e^{2x} \right)^2}~~~~~~~~~~~~;[\text{Quotient rule}]\\\\\\~~~~~~~~~~~~=\dfrac{(1+e^{2x}) \cdot \dfrac{1}{2\sqrt{3x}} \cdot 3-\left(\sqrt{3x} \right) \cdot 2 e^{2x}}{(1 + e^{2x})^2}~~~~~~~~~~~~~~~~~~~~;[\text{Chain rule}]\\\\\\$

$=\dfrac{\dfrac{\sqrt 3 (1 + e^{2x})}{2\sqrt x} -2e^{2x} \sqrt{3x}}{(1+e^{2x})^2}\\\\\\=\dfrac{\tfrac{\sqrt 3(1 +e^{2x}) - 4x\sqrt 3 e^{2x}}{2\sqrt x}}{(1+e^{2x})^2}\\\\\\=\dfrac{\sqrt 3(1+e^{2x} -4xe^{2x})}{2\sqrt x(1 +e^{2x})^2}$

7 0

2 years ago