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krek1111 [17]
3 years ago
11

Exhibit 6-2 the weight of football players is normally distributed with a mean of 200 pounds and a standard deviation of 25 poun

ds. 26. refer to exhibit 6-2. what is the minimum weight of the middle 95% of the players?
a. 196
b. 151
c. 249
Mathematics
1 answer:
Evgen [1.6K]3 years ago
5 0
The question is asking for the lower bound of the 95% two tailed Confidence interval of the normally distributed population.

95% C.I. is given by 200 + or - 1.96(25) = 200 + or - 49 = (151, 249)
Therefore, the minimum weight of the middle 95% of players is 151 pounds.
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Information about the proportion of a sample that agrees with a certain statement is given below. Use StatKey or other technolog
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Answer:

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Step-by-step explanation:

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Standard Error = √p (1 - p)/n

We are told in the question that:

In a random sample of 400 people, 112 agree and 288 disagree. Estimate the standard error using 1000 samples

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p = 112/1000

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Standard Error = √p (1 - p)/n

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