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Nadya [2.5K]
2 years ago
7

The ratio of deer to chickens is 5:3. If there are a total of 160 animals, how many are chickens?

Mathematics
2 answers:
san4es73 [151]2 years ago
5 0
5:3 = 5 + 3 = 8
160/8 = 20

20 * 5 = 100 (deers)
20 * 3 = 60 (chickens)

100:60

There are 60 chickens.

Hope that helps!


never [62]2 years ago
3 0

Answer:

The answer is 60 chickens.

Step-by-step explanation:

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Using the completing-the-square method, rewrite f(x) = x2 - 8x + 3 in vertex form.
Leto [7]

Answer:

B

Step-by-step explanation:

Given

f(x) = x² - 8x + 3

To complete the square

add/subtract ( half the coefficient of the x- term )² to x² - 8x

x² + 2(- 4)x + 16 - 16 + 3

(x - 4)² - 13 ← in vertex form → B

5 0
3 years ago
A random sample of 10 parking meters in a beach community showed the following incomes for a day. Assume the incomes are normall
Vlad1618 [11]

Answer: (2.54,6.86)

Step-by-step explanation:

Given : A random sample of 10 parking meters in a beach community showed the following incomes for a day.

We assume the incomes are normally distributed.

Mean income : \mu=\dfrac{\sum^{10}_{i=1}x_i}{n}=\dfrac{47}{10}=4.7

Standard deviation : \sigma=\sqrt{\dfrac{\sum^{10}_{i=1}{(x_i-\mu)^2}}{n}}

=\sqrt{\dfrac{(1.1)^2+(0.2)^2+(1.9)^2+(1.6)^2+(2.1)^2+(0.5)^2+(2.05)^2+(0.45)^2+(3.3)^2+(1.7)^2}{10}}

=\dfrac{30.265}{10}=3.0265

The confidence interval for the population mean (for sample size <30) is given by :-

\mu\ \pm t_{n-1, \alpha/2}\times\dfrac{\sigma}{\sqrt{n}}

Given significance level : \alpha=1-0.95=0.05

Critical value : t_{n-1,\alpha/2}=t_{9,0.025}=2.262

We assume that the population is normally distributed.

Now, the 95% confidence interval for the true mean will be :-

4.7\ \pm\ 2.262\times\dfrac{3.0265}{\sqrt{10}} \\\\\approx4.7\pm2.16=(4.7-2.16\ ,\ 4.7+2.16)=(2.54,\ 6.86)

Hence, 95% confidence interval for the true mean= (2.54,6.86)

7 0
4 years ago
Hey!! what’s the answer for this? :)
Nezavi [6.7K]
2099.5 ft

Find the angle using COS
500%650 then press 2nd function COS

39.72 degrees

Add up the measurement on the one side which comes to 1615 then divide by the COSINE of 39.72

2099.5 ft
6 0
3 years ago
For f(x)= 2x+1 and g(x)=x²-7, find (f-g)(x)<br> A.x²-2x-8<br> B.-x²+2x-6<br> C.-x²+2x+8<br> D.2x²-15
meriva

Answer:

C

Step-by-step explanation:

(2x+1) - (x²-7) = 2x + 1 - x²- + 7 = -x²- + 2x + 8

4 0
3 years ago
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Kaylis [27]
52 cents would be the answer.

Hope this helped. Would you like me to explain how I got it?
6 0
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