Answer: The answer for f= 3.1
Answer:
<em>The answer is</em> <em>{
-(5)
(36)×
-(180)</em>
Step-by-step explanation:
A polynomial with rational coefficients has roots 5 and -6i (There i is the
imaginary number not variable )
As we knew that imaginary no comes in pair . This means that if -6i is
one root then the other root will be 6i
So if we assume the lowest polynomial that is possible is given as
{
-(sum of all roots)
+(roots taken two at a time)
-(product of all roots)
{
-(5+6i+(-6i))
+(5×6i +5×(-6i) +6i×(-6i))
-(5×6i×(-6i))
= -1
<em>{
-(5)
(36)×
-(180)</em>
<em> </em>The <u>general case</u> we assume that the three previous roots and rest roots
a4,a5,a6 ...............an
-(sum of all roots)×
+(roots taken two at a
time) ×
- .......................................... (product of all roots)
Answer:
The required expression is
Step-by-step explanation:
Difference of two minus three = 2-3
Quotient of b divided by the difference of two minus three is
Therefore, the required expression is

There is nothing here for anyone to work off, If you have a picture or screenshot that would be very nice!
What we have so far:
Let set A = {<span>9, 10, 11}
Let set B = </span><span>{10, 11, 12, 13}
Let set C = A</span>∩B. This means: the intersection of A & B.
Let set D = {<span>14, 15}
Let set Universal = C</span>∪D. This means: the union of C & D where C is the intersection of A & B.
Solution:
Let us first solve for set C.
C = A∩B
C = {9, 10, 11} ∩ {10, 11, 12, 13}
C = {10, 11} <--- New value for set C
Let us now solve for set Universal.
Universal = C∪D
Unviversal = {10, 11} ∪ {14, 15}
∴ Universal = {10, 11, 14, 15} <--- What we are looking for.
Therefore, the answer is Universal = {10, 11, 14, 15}.