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Elodia [21]
3 years ago
8

A robot can complete 7 tasks in

Mathematics
1 answer:
SSSSS [86.1K]3 years ago
5 0

Answer:

5/42 is your answer take robot to complete

7 tasks = 5/6

1 task = 5/42 hour.

1 hour / (5/42 hour/task) = 15/2 tasks = 8.2 tasks.

half a task isn’t a complete task, so the answer is 8 tasks.

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In 2006,the General Social Survey (which is conducted uses a method similar to simple random sampling) included a question that
mars1129 [50]

Answer:

Assumptions are not met. Can not make confidence interval.

Step-by-step explanation:

In the General Social Survey, sample size is 1514.

The proportion of those who see themselves social is \frac{470}{1514} ≈ 0.31

To give an 95% confidence interval, we should be able to calculate margin of error of the sample mean, which is given by the formula

M±z*\frac{s}{\sqrt{N} }  where M is the mean of the sample (in the General Social Survey it is 0.31), z is z-score for the 95% confidence level(approx. 1.94), s is the standard deviation of the sample, N is the size of the sample(in this example it is 1514).

Since we don't know the standard deviation of the sample, we cannot give a confidence interval.

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3 years ago
Solve the inequality 8(x + 1) > 7(x + 2).
elixir [45]
8X + 8 > 7x + 14

subtract 7x and 8 from both sides

x > 6
5 0
3 years ago
Read 2 more answers
Find the mode: 16,12,10,15,7,916
Airida [17]

The mode is the value from a given set of data that occurs most often. It is the data with the highest frequency.

Given:

16,12,10,15,7,9,16

Form the above data given;

Rearranging for easy identification, we have;

7,9,10,12,15,16,16

\begin{gathered} 7\text{ appears once} \\ 9\text{ appears once} \\ 10\text{ appears once} \\ 12\text{ appears once} \\ 15\text{ appears once} \\ 16\text{ appears twice} \end{gathered}

From the above, we can deduce that the mode is 16 because it appears the most often. It appears twice.

Therefore, the mode is 16.

4 0
1 year ago
What is the mean absolute deviation (MAD) of the data set?
erastova [34]
The answer is 4 i think
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198 is the answer I think
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