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LUCKY_DIMON [66]

4 years ago

12

Tyler is building a fish tank in the shape of a sphere that has a diameter of 18 inches. Based on Tyler's research, it is recomm

ended to have no more than 1 goldfish for every 693 cubic inches of water. How many goldfish should Tyler buy for his fish tank? Numerical Answers Expected! Answer for Blank 1:

1 answer:

Karo-lina-s [1.5K]4 years ago

7 0

Answer: 4 fishes

Step-by-step explanation:

Hi, to answer this question we have to apply the next formula:

Volume of a sphere = 4/3 x π x (diameter/2)^3

Replacing with the values given:

V = 4/3 x π x (18/2)^3

v = 4/3 x π x (9)^3 = 3,053.63 in3

Next, we have to divide the volume of the tank by 693 in3 (volume for each fish)

3,053.63/693 =4.40 = 4 fishes

Feel free to ask for more if needed or if you did not understand something.

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3 years ago

A school is planning to construct two rectangular play areas in the playground. The length of play area A must be 1 foot longer

Anna11 [10]

Answer:

А.The system has two solutions, but only one is viable because the other results in a negative width.

Step-by-step explanation:

Given

Let:

$L_A \to$ length of play area A

$W_A \to$ width of play area A

$L_B \to$ length of play area B

$W_B \to$ width of play area B

$x \to$ Area of A

$y \to$ Area of B

From the question, we have the following:

$L_A = 1 + 4W_A$

$W_B = 2 + W_A$

$L_B = 2 + 3W_B$

$x = y$

The area of A is:

$x = L_A * W_A$

This gives:

$x = (1 + 4W_A) * W_A$

Open bracket

$x = W_A + 4W_A^2$

The area of B is:

$y = L_B * W_B$

$y = (2 + 3W_B) * ( 2 + W_A)$

Substitute: $W_B = 2 + W_A$

$y = (2 + 3(2 + W_A)) * ( 2 + W_A)$

Open brackets

$y = (2 + 6 + 3W_A) * ( 2 + W_A)$

$y = (8 + 3W_A) * ( 2 + W_A)$

Expand

$y = 16 + 8W_A + 6W_A + 3W_A^2$

$y = 16 + 14W_A + 3W_A^2$

We have that:

$x = y$

This gives:

$W_A + 4W_A^2 = 16 + 14W_A + 3W_A^2$

Collect like terms

$4W_A^2 - 3W_A^2 + W_A -14W_A - 16 =0$

$W_A^2 -13W_A - 16 =0$

Using quadratic calculator, we have:

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But the width can not be negative; So:

$W = 1.19$

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