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Anna [14]
2 years ago
15

Please help!!- - - - - - -

Mathematics
1 answer:
Alex17521 [72]2 years ago
4 0

you want a better price to pay the bill on a daily plan or manual to make sure the balance was not included to pay to the insurance to get rid if they had been approved to be paid in a year for 170m months to come and legendary domortu for a few days now for a long weekend and Golden is a bit crazy but I'm not even getting out here to get it out and I don't want you want it or don't know me or you know I am not a big fan of your music and legendary domortu but if someone could give them some pets from your bank to help us find out the details for 200m

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for 3 weeks, you earn 1.05 per day for doing around the house . your parents give you a 7.50 bonus . how much money do you have
gladu [14]
Multiply 3 times 1.05= 3.15, that is who much he got in 3 weeks.now add 3.15 and 7.50 witch is 10.65
4 0
3 years ago
1.work out 1/2 + 5/6
Serggg [28]
1.  First find the LCD of the two fractions.
They share the denominator 6.
Turn 1/2 into a fraction with a denominator of 6.
2*3=6,  so 1*3=3
3/6
Now add.
Leave denominators alone,  but add numerators.
3+5=8
8/6
Now simplify.
Divide both by 2.
8/2=4
6/2=3
4/3 is your answer or 1 1/3
2.  Multiply straight across.
3*2=6
4*7=28
6/28
Simplify
You get 3/14 as your answer.
3 0
4 years ago
a new bottle that says it gives you 30% more free. Use the drop-down menus to build an equation that could be used to find the s
Alina [70]
What are the answer choices
4 0
3 years ago
Find the area of the shaded region ​
o-na [289]

so hmmm let's get the area of the whole hexagon, and then get the area of the circle inside it, then <u>subtract the area of the circle from that of the hexagon's</u>, what's leftover is what we didn't subtract, namely the shaded part.

\textit{area of a regular polygon}\\\\ A=\cfrac{1}{4}ns^2\cot\stackrel{\stackrel{degrees}{\downarrow }}{\left( \frac{180}{n} \right)}~ \begin{cases} n=\textit{number of sides}\\ s=\textit{length of a side}\\[-0.5em] \hrulefill\\ n=\stackrel{hexagon}{6}\\ s=\frac{9}{2} \end{cases}\implies A=\cfrac{1}{4}(6)\left( \cfrac{9}{2} \right)^2 \cot\left( \cfrac{180}{6} \right)

A=\cfrac{1}{4}(6)\cfrac{9^2}{2^2} \cot(30^o)\implies A=\cfrac{243}{8}\cot(30^o)\implies A=\cfrac{243\sqrt{3}}{8} \\\\[-0.35em] ~\dotfill\\\\ \textit{area of circle}\\\\ A=\pi r^2~~ \begin{cases} r=radius\\[-0.5em] \hrulefill\\ r=\frac{4}{5} \end{cases}\implies A=\pi \left( \cfrac{4}{5} \right)^2\implies A=\cfrac{16\pi }{25} \\\\[-0.35em] ~\dotfill

\stackrel{\textit{area of the hexagon}}{\cfrac{243\sqrt{3}}{8}}~~ - ~~\stackrel{\textit{area of the circle}}{\cfrac{16\pi }{25}}\implies \cfrac{6075\sqrt{3}-128\pi }{200}

5 0
2 years ago
Whats the answer for taking its square root?<img src="https://tex.z-dn.net/?f=y%5E%7B2%7D%20%3D%2068" id="TexFormula1" title="y^
Reil [10]

Answer:

y=\pm 2\sqrt{17}

Step-by-step explanation:

y=\pm \sqrt{68} \\ \\ y=\pm 2\sqrt{17}

4 0
2 years ago
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