Question

Let ​ f(x)=x^2−10x−11 ​. Enter the x-intercepts of the quadratic function in the boxes.

Answer 1

ANSWER

The y-intercept is (0,-11)

The x-intercepts are:

(-1,0) and (11,0)

EXPLANATION

The given function is

$f(x) = {x}^{2} - 10x - 11$

To find the y-intercept, we put x=0 into the function.

$f(0) = {0}^{2} - 10(0) - 11$

$f(0) = - 11$

The y-intercept is (0,-11)

To find the x-intercepts, we put f(x)=0.

${x}^{2} - 10x - 11 = 0$

$(x + 1)(x - 11) = 0$

This implies that,

$x = - 1 \: or \: x = 11$

The x-intercepts are:

(-1,0) and (11,0)