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Oduvanchick [21]
2 years ago
9

Help, please the question and thank you

Mathematics
1 answer:
Alex Ar [27]2 years ago
5 0
Choose the first one becauseA(1,3) and after the dilatation the x and y of A become three times as the original one so it is(3, 9)
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The formula h=40 +50t+10t2 can be used to find the height h, in meters, of an object shot upward from the top of a 40 meter
Neko [114]
U add up all the intergers subtract by 40 and u get your answer which is h=22
4 0
4 years ago
Two diameters of circle P are AB and CD. Find the measure of arc ACD and arc AC when arc AD has a measure of 20 degrees
steposvetlana [31]

Answer:

Hence measure of arc ACD and arc AC are 340 degrees and 160 degrees respectively.

Step-by-step explanation:

Given:

A Circle with p as center and AB and CD as 2 diameters for a circle.

To Find:

Measure of ACD, and arc AC when arc AD is 20 degrees.

Solution:

<em>As we know that , Diameter is biggest chord which passes through center of circle,</em>

<em>Hence it divides the circle into two equal parts and making center as midpoint of it</em> .

(Refer the attachment)

angle APD=20 degree or arc AD=20 degree.

So AB as diameter ,so  arc DB=160 degree  or BPD=160 degree as A-B-P are

and angle APD and BPC are vertical opposite angles so they are congruent BPC=20 degree

Now,

points A,C,B,D,A makes circle which measures 360 degrees.

to find ACD

measure of ACD=360-(meaure of arc AD or angle APD)

=360-20

=340 degree.

Now arc AC,

as AB is diameter with p as midpoint ,A-P-B

arc APB=180 and arc BC=20 or angle BPC=20 degrees.

For measure of arc AC= measure of arc APB- arc BC

arc AC=180-20 degrees.

arc AC=160 degrees.

5 0
4 years ago
Imagine you had 40 one-metre sections of fencing.
Darya [45]

Answer: If I’m not mistaken, the largest area is 75 m2 and the smallest is 2 m2

Step-by-step explanation:

For both : since they are asking for the area, you should calculate the perimeter.

So for the largest area, since you know that you have 40 fences, and each are 1 meter long, and they’re also asking for the largest rectangular area, this means that only the opposite sides will have the same length, so in order to divide the rectangle with the 40 one-meter fences, the biggest sides have to be 15 meters long (so for both : 15x2=30 meters). Then you deduct from 40, 30 : 40-30 = 10 which then you can devide by 2 and find 5 + 5 and that means that the 2 smallest sides will be 5 meters long each. Then finally to calculate the perimeter you should do the biggest side multiplied by the smallest side : 15 x 5 and you find 75 m2 (squaremeters), if I’m not mistaken.

And for the smallest area you take the smallest possibilities knowing that only the opposite sides should have the same length and not all of them, so you do 1 x 2 and you find 2 m2.

8 0
4 years ago
Un cono ha l'area laterale di 255 pigreco cm^2, l'apotema di 17 cm e pesa 900 pigreco g. Calcola il peso specifico del materiale
valkas [14]

Answer:

The specific weight is 1.5\frac{g}{cm^{3}}

Step-by-step explanation:

The question in English

A cone has a lateral area of 255 pi cm^2, an apothem of 17 cm and weighs 900 pi g. It calculates the specific weight of the material of which it is composed

step 1

Find the radius of the cone

we know that

The lateral area of a cone is equal to

LA=\pi rl

we have

LA=255\pi\ cm^{2}

l=17\ cm

substitute the values

255\pi=\pi r(17)

Simplify

255=r(17)

r=255/(17)=15\ cm

step 2

Find the height of the cone

Applying the Pythagoras Theorem

l^{2} =r^{2} +h^{2}

substitute the values and solve for h

17^{2} =15^{2} +h^{2}

h^{2}=17^{2}-15^{2}

h^{2}=64

h=8\ cm

step 3

Find the volume of the cone

The volume of the cone is equal to

V=\frac{1}{3}\pi r^{2}h

substitute the values

V=\frac{1}{3}\pi (15)^{2}(8)

V=600\pi\ cm^{3}

step 4

Find the specific weight

Divide the mass by the volume

\frac{900\pi }{600\pi}=1.5\frac{g}{cm^{3}}

4 0
4 years ago
Plz help i suck art math
True [87]

um 600?? I'm sorry if that's wrong

5 0
3 years ago
Read 2 more answers
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