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3 years ago

A map has a scale showing 3 inches represents 11 km. How many miles apart

Mathematics

1 answer:

jekas [21]3 years ago

3 0

Answer:

Step-by-step explanation:

Direct proportion.

Distant between two cities= 11/3 * 9.7 = 106.7/3 = 35.56 km

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The steps to solving the expression the quantity of the sum of three squared plus four divided by the absolute value of negative

bearhunter [10]

Answer:

Step 3 should be ((9+4)/(0.25))-10.4 divided 4

Step 6 should be 52 - 2.6

I got it right on my exam :)

7 0

10 months ago

Your cell phone company charges $20 per month for 500 minutes plus an additional

Alex_Xolod [135]

Answer:

$21

Step-by-step explanation:

$20 for the 500 minutes

We still have to pay for 10 minutes.

10 cents per minute.

10centsx10 minutes.

100 cents, also known as 1 dollar.

$20 plus $1 means the answer is $21.

Hope this helps!

-AxekickNebulite

8 0

2 years ago

Fraction equal to 1 that has 29 as a denominatior

d1i1m1o1n [39]

Answer:

29/29

Step-by-step explanation:

/ means division so 29/29=1

4 0

3 years ago

Plz i need help What is the volume of the rectangular prism? show how you did it

Vesnalui [34]

The formula for volume is V=LWH

So in this example we have 10.4*5*8

So 8*5=40

40*10.4=416

So the volume is 416 cubic mm

Hope that helped

4 0

3 years ago

If cos() = − 2 3 and is in Quadrant III, find tan() cot() + csc(). Incorrect: Your answer is incorrect.

nydimaria [60]

Answer:

$\tan(\theta) \cdot \cot(\theta) + \csc(\theta) = \frac{5 - 3\sqrt 5}{5}$

Step-by-step explanation:

Given

$\cos(\theta) = -\frac{2}{3}$

$\theta \to$ Quadrant III

Required

Determine $\tan(\theta) \cdot \cot(\theta) + \csc(\theta)$

We have:

$\cos(\theta) = -\frac{2}{3}$

We know that:

$\sin^2(\theta) + \cos^2(\theta) = 1$

This gives:

$\sin^2(\theta) + (-\frac{2}{3})^2 = 1$

$\sin^2(\theta) + (\frac{4}{9}) = 1$

Collect like terms

$\sin^2(\theta) = 1 - \frac{4}{9}$

Take LCM and solve

$\sin^2(\theta) = \frac{9 -4}{9}$

$\sin^2(\theta) = \frac{5}{9}$

Take the square roots of both sides

$\sin(\theta) = \±\frac{\sqrt 5}{3}$

Sin is negative in quadrant III. So:

$\sin(\theta) = -\frac{\sqrt 5}{3}$

Calculate $\csc(\theta)$

$\csc(\theta) = \frac{1}{\sin(\theta)}$

We have: $\sin(\theta) = -\frac{\sqrt 5}{3}$

So:

$\csc(\theta) = \frac{1}{-\frac{\sqrt 5}{3}}$

$\csc(\theta) = \frac{-3}{\sqrt 5}$

Rationalize

$\csc(\theta) = \frac{-3}{\sqrt 5}*\frac{\sqrt 5}{\sqrt 5}$

$\csc(\theta) = \frac{-3\sqrt 5}{5}$

So, we have:

$\tan(\theta) \cdot \cot(\theta) + \csc(\theta)$

$\tan(\theta) \cdot \cot(\theta) + \csc(\theta) = \tan(\theta) \cdot \frac{1}{\tan(\theta)} + \csc(\theta)$

$\tan(\theta) \cdot \cot(\theta) + \csc(\theta) = 1 + \csc(\theta)$

Substitute: $\csc(\theta) = \frac{-3\sqrt 5}{5}$

$\tan(\theta) \cdot \cot(\theta) + \csc(\theta) = 1 -\frac{3\sqrt 5}{5}$

Take LCM

$\tan(\theta) \cdot \cot(\theta) + \csc(\theta) = \frac{5 - 3\sqrt 5}{5}$

6 0

3 years ago