Question

Simultaneous linear equation

Answer 1

Step-by-step explanation:

a) 3x + 5y = 8

4x - 3y = 1

• using the elimination method:

3x + 5y = 8 (×4)

4x -3y = 1 (×3)

12x + 20y = 32

12x -9y = 3

subract 12x from both equation:

20y - - 9y= 32 -3

20y +9y = 29

29y= 29

y= 29/29

y= 1

- substituting y= 1 in :

4x - 3y= 1

4x - 3(1) = 1

4x -3 = 1

4x = 1 + 3

x = 4/4

x= 1

b) 6p+ 4q = 20

5p - 2q = 6

• using the elimination method:

6p + 4q = 20

5p - 2q = 6 (×2)

6p + 4q = 20

10p - 4q = 12

add 4q + -4q to eliminate q.

6p+ 10p = 20+12

16p = 32

p = 32/ 16

p = 2

- subtituting p = 2 in :

5p - 2q = 6

5(2) -2q =6

10 -2q = 6

-2q = 6 - 10

q = -4 / -2

q = 2

hope this helps you,

-s.

Answer 2

Answer:

a. x = 1 / y = 1

b. p = 2 / q = 2

Step-by-step explanation:

a.

3x + 5y = 8 ________( 1 )

4x - 3y = 1________ ( 2 )

( 1 ) × 3 ____ 9x + 15y = 24 _____ ( 3 )

( 2 ) × 5____ 20x - 15y = 5 _____ ( 4 )

( 3 ) + ( 4 )

$9x + 15y + 20x - 15y = 24 + 5 \\ 9x + 20x + 15y - 15y = 29 \\ 29x = 29 \\ x = \frac{29}{29} \\ x = 1$

x = 1 substitute to ( 1 ) ,

$3x + 5y = 8 \\ 3(1) + 5y = 8 \\ 3 + 5y = 8 \\ 5y = 8 - 3 \\ 5y = 5 \\ y = \frac{5}{5} \\ x = 1$

b.

6p + 4q = 20_______ ( 1 )

5p – 2q = 6 _______ ( 2 )

( 2 ) × 2 ____ 10p - 4q = 12 _______ ( 3 )

( 1 ) + ( 3 )

$6p + 4q + 10p - 4q = 20 + 12 \\ 6p + 10p + 4q - 4q = 32 \\ 16p = 32 \\ p = \frac{32}{16} \\ p = 2$

p = 2 substitute to ( 1 ) ,

$6p + 4q = 20 \\ 6(2) + 4q = 20 \\ 12 + 4q = 20 \\ 4q = 20 - 12 \\ 4q = 8 \\ q = \frac{8}{4} \\ q = 2$