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Serjik [45]
3 years ago
10

Please I need it now will give brainliest

Mathematics
1 answer:
Nat2105 [25]3 years ago
4 0

Answer:

  (a)  Yes, multiplying every length of a Pythagorean triple by the same whole number results in a Pythagorean triple.

Step-by-step explanation:

In general, scaling the numbers involved in a relationship does not change their relationship.

If we have ...

  a² +b² = c²

and we scale each number by a factor of k, then we get ...

  (ka)² +(kb)² = (kc)²

  k²a² +k²b² = k²c²

  k²(a² +b²) = k²c² . . . . same result as multiplying the original relation by k²

Leon is correct that multiplying a Pythagorean triple by a constant gives another Pythagorean triple.

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PLEASE HELP!!
Marysya12 [62]
The first system of equations has infinite solutions because you can write one equation as a linear combination of the other.The second system of equations has no solution because mathematically an incoherence results -14 = -2 / 7I attach the solutions for greater understanding.
x-4y=12; 5x-20y=60 --> infinitely many
y-7x=-14; 7y-49x=-2 --> none

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3 years ago
the perimeter of the square shown is 4(x+3.3) meters. What is the value of x if the perimeter is 28 meters​
Lana71 [14]

28 = 4(x+3.3)

7=x+3.3

3.7=x

8 0
4 years ago
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Identify the scale factor used to graph the<br> image below.
fomenos
Scale factor= 1/2 :)
6 0
3 years ago
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KonstantinChe [14]

Answer:

Commutative

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5 0
3 years ago
In a journey of 15 miles, two third distance was travelled with 40 mph and remaining with 60 mph. How much time does the journey
Ad libitum [116K]

The first step in solving this question is to split the journey into 2 parts. In the first part of the journey, \frac{2}{3} \times 15 = 10 miles are covered at a speed of 40 mph. In the second part the journey 5 miles are covered at a speed of 60 mph.

The equation to compute the time of a journey  given the speed and distance is t=\frac{d}{s} where t is the time, s is the speed and d is the distance.

The time for the first part of the journey is calculated as shown below,

t=\frac{d}{t} \\t=\frac{10m}{40mph} =\frac{10}{40} h.

The time for the second part of the journey is calculated as follows,

t=\frac{d}{t} \\t=\frac{5m}{60mph} =\frac{5}{60} h.

The total time is the sum of the times taken to cover each part of the journey and is calculated as shown below,

t=\frac{10}{40} h+\frac{5}{60} =\frac{30+10}{120} h=\frac{40}{120}h =\frac{1}{3} h

The time to cover the journey is a third of an hour or 20 minutes.

5 0
3 years ago
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