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mr_godi [17]
3 years ago
13

John uses 9 eggs to make 5 burritos. How many burritos can he make with 27 eggs?

Mathematics
2 answers:
Mademuasel [1]3 years ago
7 0
Hello!

John uses 9 eggs to make 5 burritos.

27 ÷ 9 = 3

Nine goes into seven three times.

5 × 3 = 15

ANSWER:

John can make 15 burritos with 27 eggs.
Ahat [919]3 years ago
3 0
He can make 15 burritos
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Step-by-step explanation:

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The first step when dividing 9m2 − 4m − 6 by 3m is shown. Which could be the next step? 3m − − 3m − − 3m − − 3m − −
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3 years ago
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Please answer! this is an important exam that im taking right now.
Scorpion4ik [409]

Answer:

Required ordered pair is (0,0) for system of equation

Step-by-step explanation:

The given system of equation is

A). 9^{12x} = 9^{3y}

B). y^{4} - 9y^{2} x^{2} =16y

On simplifying the equation A

9^{12x} = 9^{3y}

Take log on both side,

(12x) (log9) = (3y) (log9)

4x=y

To find the solution of the system of the equation :

Replacing value of y=4x in equation B,

y^{4} - 9y^{2} x^{2} =16y

(4x)^{4} - 9(4x)^{2} x^{2} =16(4x)

256x^{4} - 144x^{2} x^{2} =64x

256x^{4} - 144x^{4}=64x

112x^{4}=64x

We get,

x=0 and x=0.829

Since, 0.829 is not integer number

Only solution of equations is x=0

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3 years ago
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Temperature transducers of a certain type are shipped in batches of 50. A sample of 58 batches was selected, and the number of t
andrew11 [14]

Answer:

a) X        Freq.         Rel Freq.

__________________________

0           7              (7/58) = 0.121

1            10            (10/58)=0.172

2           13            (13/58) =0.224

3           14            (14/58)=0.241

4           6              (6/58)=0.103

5           3              (3/58)=0.052

6           3              (3/58)=0.052

7            1              (1/58) =0.017

8            1              (1/58)=0.017

_________________________

Total     58                 1.00

b) \frac{7+10+13+14+6}{58}= \frac{50}{58}=0.862

Step-by-step explanation:

Assuming this question: Temperature transducers of a certain type are shipped in batches of 50. A sample of 60 batches was selected, and the number of transducers in each batch not conforming to design specifications was determined, resulting in the following data:

2,1,2,4,0,1,3,2,0,5,3,3,1,3,2,4,7,0,2,3,

0,4,2,1,3,1,1,3,4,2,3,2,2,8,4,5,1,3,1,

5,0,2,3,2,1,0,6,4,2,1,6,0,3,3,3,6,2,3

(a) Determine frequencies and relative frequencies for the observed values of x = number of nonconforming transducers in a batch. (Round your relative frequencies to three decimal places.)

For this case first we order the dataset on increasing way and we got:

0 0 0 0 0 0 0

1 1 1 1 1 1 1 1 1 1

2 2 2 2  2 2 2 2 2 2 2 2 2

3 3 3 3 3 3 3 3 3 3 3 3  3 3

4 4 4 4 4 4

5 5 5

6 6 6

7

8

And we can construct the following table:

X        Freq.         Rel Freq.

__________________________

0           7              (7/58) = 0.121

1            10            (10/58)=0.172

2           13            (13/58) =0.224

3           14            (14/58)=0.241

4           6              (6/58)=0.103

5           3              (3/58)=0.052

6           3              (3/58)=0.052

7            1              (1/58) =0.017

8            1              (1/58)=0.017

_________________________

Total     58                 1.00

(b) What proportion of batches in the sample have at most four nonconforming transducers? (Round your answer to three decimal places.)

For this case this proportion would be:

\frac{7+10+13+14+6}{58}= \frac{50}{58}=0.862

4 0
3 years ago
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