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timama [110]
3 years ago
9

5. A solid has a circle of radius r as its base. All sections of the solid perpendicular to the diameter along the x-axis are is

osceles right angled triangles. Find the volume of the solid.(Hint: you have to distinguish two cases). 2
Mathematics
1 answer:
AleksandrR [38]3 years ago
4 0

Answer:

 \frac{16r^3}{3}

Step-by-step explanation:

In this cross sections problem, we can integrate from -r to +r (so that the integral covers the entire base of the solid).

\int\limits^r_a {2(x^2+r^2 )} \, dx

The formatting for the integral did not let me put -r on the lower bound, so i replaced it with a, just know that a represents -r here.

Evaluating the integral gives use that it is equal to;

\frac{16r^3}{3}

Caution: this answer may not meet your needs, but this is the answer I have come up with with the given information.

If you found this answer helpful please consider leaving 5 stars, giving it a like, or if you asked this question, mark this answer as Brainliest. Thanks!

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A poll that does not attempt to generate a random sample, but instead invites people to volunteer to participate is called:_____
Helga [31]

Answer:

Self selection sampling.

Step-by-step explanation:

A poll that does not attempt to generate a random sample, but instead invites people to volunteer to participate is called - self selection sampling.

Self-selection sampling is a sampling method where researchers allow the people or individuals, to choose to take part in research on their own accord.

6 0
3 years ago
Find the domain and the range of the relation. Determine whether the relation is a function.
andre [41]

Answer:

Domain: {-6, -1, 7}

Range: {-9, 0, 9}

The relation is not a function.

Step-by-step explanation:

Given the relation: t{(−1,0),(7,0),(−1,9),(−6,−9)}

In the ordered pairs:

  • The domain is the set of all "x" values
  • The range is set of all "y" values
  • We do not need to list any repeated value in the range/domain more than once.

Domain: {-6, -1, 7}

Range: {-9, 0, 9}

Next, we determine whether the relation is a function.

For a relation to be a function, each x must correspond with only one y value.

However, as is observed in the mapping attached below:

  • f(-1)=0
  • f(-1)=9

The x-value (-1) corresponds to two y-values (0 and 9)

Therefore, the relation is not a function.

8 0
3 years ago
An electronics store makes a profit of $72 for every standard CD player sold and $90 for every portable CD sold. the managers ta
Alisiya [41]

s -> no: of standard CD players sold

p -> no: of portable CD players sold.

Profit Per Standard CD player=72$

Profit per Portable CD player =90$

Target Amount =360$

<em>I</em><em>n</em><em> </em><em>short</em><em>:</em><em> </em><em>The</em><em> </em><em>combined</em><em> </em><em>sales</em><em> </em><em>of</em><em> </em><em>Both</em><em> </em><em>the</em><em> </em><em>CD</em><em> </em><em>player</em><em>'s</em><em> </em><em>must</em><em> </em><em>exceed</em><em> </em><em>or</em><em> </em><em>atleast</em><em> </em><em>become</em><em> </em><em>equal</em><em> </em><em>to</em><em> </em><em>3</em><em>6</em><em>0</em><em>$</em><em> </em><em>to</em><em> </em><em>a</em><em>c</em><em>q</em><em>u</em><em>i</em><em>r</em><em>e</em><em> </em><em>the</em><em> </em><em>target</em><em>.</em>

<em>Thus</em><em>;</em><em> </em><em>the</em><em> </em><em>inequality</em><em> </em><em>can</em><em> </em><em>be</em><em> </em><em>stated</em><em> </em><em>as</em><em>:</em>

<em> </em><em> </em><em> </em><em> </em><em> </em><em>7</em><em>2</em><em>(</em><em>s</em><em>)</em><em> </em><em>+</em><em> </em><em>9</em><em>0</em><em>(</em><em>p</em><em>)</em><em> </em><em>≥</em><em>3</em><em>6</em><em>0</em>

<em>-</em><em>></em><em> </em><em>3</em><em>6</em><em>(</em><em>s</em><em>)</em><em> </em><em>+</em><em> </em><em>4</em><em>5</em><em>(</em><em>p</em><em>)</em><em> </em><em>≥</em><em>1</em><em>8</em><em>0</em>

<em>-</em><em>></em><em> </em><em>1</em><em>2</em><em>(</em><em>s</em><em>)</em><em> </em><em>+</em><em>1</em><em>5</em><em>(</em><em>p</em><em>)</em><em> </em><em>≥</em><em> </em><em>9</em><em>0</em>

<em> </em><em> </em><u><em>_</em><em>_</em><em>_</em><em>_</em><em>_</em><em>_</em><em>_</em><em>_</em><em>_</em><em>_</em><em>_</em><em>_</em><em>_</em><em>_</em><em>_</em></u>

<em>-</em><em>></em><u>|<em> </em><em>4</em><em>(</em><em>s</em><em>)</em><em> </em><em>+</em><em> </em><em>5</em><em>(</em><em>p</em><em>)</em><em> </em><em>≥</em><em> </em><em>3</em><em>0</em><em> </em><em> </em><em> </em><em> </em>|</u>

<em><u>Hope it helps...</u></em>

<em><u>Hope it helps...Regards;</u></em>

<em><u>Hope it helps...Regards;Leukonov/Olegion.</u></em>

8 0
3 years ago
Please help I've been have trouble with it.
kakasveta [241]
It should be Answer D. I hope this helps. I also hope you have a great day!!!
3 0
3 years ago
Read 2 more answers
If the dimensions of a rectangle with a perimeter of 12 cm are doubled, what will be
exis [7]

Step-by-step explanation:

the perimeter is the sum of the 4 individual sides.

if the sides are doubled, so is the sum of them.

therefore, the new perimeter is then

12×2 = 24 cm

3 0
2 years ago
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