The length of the hypotenuse is 5ft
a^2+b^2=c^2
3^2+4^2=c^2
9+16=c^2
c^2=25
sqrt c^2= sqrt 25
c=5
Therefore, the length of the hypotenuse is 5th
:)
Answer:
x=-3,x1/2
Step-by-step explanation:
f(x)=(2x-1)(x+3)
TI find x intercept/zero substitute
f(x)=0
0=(2x-1)x(x+3)
swap the sides of the equation
(2x-1)x(x+3)=0
when the product of factors equals 0,at least one factor is zero
2x-1=0
x+3=0
solve the equation for x
x=1/2
x+3=0
solve the equation of x
x=-3
The equation has two solution
x=-3
x=1/2
Not sure can you explain a little more
Answer:
![(3,29)](https://tex.z-dn.net/?f=%283%2C29%29)
Step-by-step explanation:
There is a formula that can be used to find the x-value of the vertex of the parabola. This formula is ![x=\frac{-b}{2a}](https://tex.z-dn.net/?f=x%3D%5Cfrac%7B-b%7D%7B2a%7D)
We have the function ![g(x)=-3x^2+18x+2](https://tex.z-dn.net/?f=g%28x%29%3D-3x%5E2%2B18x%2B2)
From this function, we can find that
![a=-3\\b=18\\c=2](https://tex.z-dn.net/?f=a%3D-3%5C%5Cb%3D18%5C%5Cc%3D2)
We can plug in our know values into the formula to get
![x=\frac{-18}{2(-3)\\} \\x=\frac{-18}{-6} \\\\x=3](https://tex.z-dn.net/?f=x%3D%5Cfrac%7B-18%7D%7B2%28-3%29%5C%5C%7D%20%5C%5Cx%3D%5Cfrac%7B-18%7D%7B-6%7D%20%5C%5C%5C%5Cx%3D3)
Then we can plug in our x-value to find the y-value of the vertex
![g(3)=-3(3)^2+18(3)+2\\\\g(3)=-3(9)+54+2\\\\g(3)=-27+54+2\\\\g(3)=29](https://tex.z-dn.net/?f=g%283%29%3D-3%283%29%5E2%2B18%283%29%2B2%5C%5C%5C%5Cg%283%29%3D-3%289%29%2B54%2B2%5C%5C%5C%5Cg%283%29%3D-27%2B54%2B2%5C%5C%5C%5Cg%283%29%3D29)
This means that the vertex would be ![(3,29)](https://tex.z-dn.net/?f=%283%2C29%29)