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Ksenya-84 [330]
3 years ago
12

8÷2+(18−12)4−5×12 sos please help

Mathematics
1 answer:
Anuta_ua [19.1K]3 years ago
7 0
-32

Explanation:
8/2 + (18-12)4-5•12
8/2 + (6)4 - 5 • 12
4 + 24 - 60
28 - 60
-32

Hope this helps!
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What is 9 times 52 using mental math property
arsen [322]
Everyone works differently in mental meth.

To calculate 9*52, we note that 9=10-1, so mentally calculate
9(52)
=(10-1)(52)
=520-52   [ subtract 20 from each number]
=(520-20)-(52-20)  
=500-32
=468.

Alternatively,
9*52=9*50+9*2=450+18=468

If  you're good with multiplication and division,
9*52=3*3(52)=3*156=450+18=468


3 0
4 years ago
Which ordered pair is a solution of the equation?<br> y+1 =3(2 – 4)
Kisachek [45]
The correct answer is C!
3 0
3 years ago
Look at the following number sequence.
pantera1 [17]

Answer:

18, 21

Step-by-step explanation:

There is a difference of 3 between any two consecutive term ( succeeding - preceding)

Hence 15 + 3 = 18

& 18 + 3 = 21 are the required terms.

4 0
4 years ago
what is the solution to the system of equations: x- - y-z = 2, - x - 3 y - 2 z + 4, -x - 2 z = 10
ladessa [460]

Given equations are x- - y-z = 2, - x - 3 y - 2 z + 4, -x - 2 z = 10 .

It seems you have missed to write = in the 2nd equation so i have fixed the sign and going to solve the following system of equations:

x-y-z=2 ...(i)

-x-3y-2z=4 ...(ii)

-x-2z=10 ...(iii)


solve (i) for x

x=2+y+z ...(iv)

plug (iv) into (ii)

-x-3y-2z=4

-(2+y+z)-3y-2z=4

-2-y-z-3y-2z=4

-2-4y-3z=4

-4y-3z=6...(v)


plug (iv) into (iii)

-x-2z=10

-(2+y+z)-2z=10

-2-y-z-2z=10

-2-y-3z=10

-y=12+3z

y=-12-3z...(vi)


plug (vi) into (v)

-4y-3z=6

-4(-12-3z)-3z=6

48+12z-3z=6

48+9z=6

9z=-42

z=-14/3


Now plug value of z into (vi)

y=-12-3z=-12-3(-14/3)=-12+14=2

y=2


plug value of y and z into (iv)

x=2+y+z=2+2-14/3=-2/3


Hence final answer is x=-2/3, y=2, z=-14/3

3 0
3 years ago
Multiply.
Nady [450]

\boxed{3\sqrt{22}\sqrt{58}\sqrt{18}=18\sqrt{638}}

<h2>Explanation:</h2>

Here we have the following expression:

3\sqrt{22}\sqrt{58}\sqrt{18}

So we need to simplify that radical expression. By property of radicals we know that:

\sqrt[n]{a}\sqrt[n]{b}=\sqrt[n]{ab}

So:

3\sqrt{22}\sqrt{58}\sqrt{18}=3\sqrt{22\times 58 \times 18}=3\sqrt{22968}

The prime factorization of 22968 is:

22968=2^3\cdot 3^2\cdot11\cdot 29

Hence:

3\sqrt{22968}=3\sqrt{2^3\cdot 3^2\cdot11\cdot 29}=3\sqrt{2^2\cdot 3^2\cdot 2\cdot 11\cdot 29}

By property:

\sqrt[n]{a^n}=a

So:

3\sqrt{2^2\cdot 3^2\cdot 2\cdot 11\cdot 29} \\ \\ 3(2)(3)\sqrt{2\cdot 11\cdot 29}=18\sqrt{638}

Finally:

\boxed{3\sqrt{22}\sqrt{58}\sqrt{18}=18\sqrt{638}}

<h2>Learn more:</h2>

Radical expressions: brainly.com/question/13452541

#LearnWithBrainly

3 0
3 years ago
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