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BabaBlast [244]
3 years ago
6

What is y=-2(x+1)(x-2) in standard form​

Mathematics
1 answer:
juin [17]3 years ago
6 0

\leadsto \tt y=-2(x+1)(x-2)

\\  \\

\leadsto \tt y=-2(x {}^{2}  - 2x + x - 2)

\\  \\

\leadsto \tt y=-2(x {}^{2}  - x - 2)

\\  \\

\leadsto \tt y=-2x {}^{2}  +  x  +  2

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Simplify the following expression:<br> Sqrt (-16) + sqrt(-25+5)
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(4 + 2√5) i

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√(-16) + √(-25 + 5)

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(4 + 2√5) i

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In the "magic square" at the right, the four numbers
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Can someone give me the answers for theses I’ve been lost all day with online school
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True. That is a function.

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6 0
3 years ago
A blimp can be seen flying at an altitude of 5500 feet above a motor speedway during a race. The slanted distance directly to th
Vladimir [108]

Answer:

The expression of h as function of x is   h = \sqrt{(d + 5500) (d - 5500)}

Step-by-step explanation:

Given as :

The distance of blimp  (AB) = 5500 feet

The slanted distance to the pagoda (BC) = d feet

The horizontal distance (AC) = h

Let the angle made between slanted distance and horizontal distance be Ф

So , cos Ф = \frac{AC}{BC} = \frac{h}{d}

And sin Ф =  \frac{AB}{BC} = \frac{5500}{d}

∵, cos²Ф = 1 - sin²Ф

So, (\frac{h}{d})^{2} = 1 - (\frac{5500}{d})^{2}

Or, (\frac{h}{d})^{2} = (\frac{d^{2}- 5500^{2}}{d^{2}})

Or,                                     h² = d² - 5500²

∴                                        h = \sqrt{d^{2}- 5500^{2}}

Or,                                     h = \sqrt{(d + 5500) (d - 5500)}

Hence The expression of h as function of x is   h = \sqrt{(d + 5500) (d - 5500)}     Answer

3 0
3 years ago
Which exponential equation is equivalent to the logarithmic equation below? log 478= a
marta [7]
\hbox{if } \log_x y=z \hbox{ then } x^z=y \\ \\&#10;\log 478=a \\ \downarrow \\&#10;\log_{10} 478=a \\ \Downarrow \\ \boxed{10^a=478}

The answer is A.
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