Answer:
38.5
Step-by-step explanation:
812.30/83 = 9.78674698.....
Nearest tenth means one number under decimal place so...
812.30/83 ~ 9.8
Explanation: The 9.7... rounded up to 9.8 because the number after the tenths place (in this case the number after the 7) is greater or equal to 5.
Answer: The square root of π has attracted attention for almost as long as π itself. When you’re an ancient Greek mathematician studying circles and squares and playing with straightedges and compasses, it’s natural to try to find a circle and a square that have the same area. If you start with the circle and try to find the square, that’s called squaring the circle. If your circle has radius r=1, then its area is πr2 = π, so a square with side-length s has the same area as your circle if s2 = π, that is, if s = sqrt(π). It’s well-known that squaring the circle is impossible in the sense that, if you use the classic Greek tools in the classic Greek manner, you can’t construct a square whose side-length is sqrt(π) (even though you can approximate it as closely as you like); see David Richeson’s new book listed in the References for lots more details about this. But what’s less well-known is that there are (at least!) two other places in mathematics where the square root of π crops up: an infinite product that on its surface makes no sense, and a calculus problem that you can use a surface to solve.
Step-by-step explanation: this is the same paragraph The square root of π has attracted attention for almost as long as π itself. When you’re an ancient Greek mathematician studying circles and squares and playing with straightedges and compasses, it’s natural to try to find a circle and a square that have the same area. If you start with the circle and try to find the square, that’s called squaring the circle. If your circle has radius r=1, then its area is πr2 = π, so a square with side-length s has the same area as your circle if s2 = π, that is, if s = sqrt(π). It’s well-known that squaring the circle is impossible in the sense that, if you use the classic Greek tools in the classic Greek manner, you can’t construct a square whose side-length is sqrt(π) (even though you can approximate it as closely as you like); see David Richeson’s new book listed in the References for lots more details about this. But what’s less well-known is that there are (at least!) two other places in mathematics where the square root of π crops up: an infinite product that on its surface makes no sense, and a calculus problem that you can use a surface to solve.
Hey there!
The perimeter of the floor plan is 30 inches.
Perimeter is length + length + width + width, so we can do 9 + 9 + 6 + 6 = 30
The area of the floor plan is 54 inches²
Area is length x width, so we can do 9 x 6 = 54
The perimeter of the actual size is 105 feet
First, we can solve the dimensions for the actual size. We know that 2 inches = 7 feet, so we can do 7/2 and get 3.5. This means that for every 1 inch, it's 3.5 feet. Then, we multiply the dimensions by 3.5:
9 x 3.5 = 31.5 feet
6 x 3.5 = 21 feet
Then we solve for perimeter. Perimeter is length + length + width + width, so we can do 31.5 + 31.5 + 21 + 21 = 105
The area of the actual size is 661.5 inches²
Area is length x width, so we can do 31.5 x 21 = 661.5
Hope this helps! Tell me if you need more help.
