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3 years ago

Solve the following inequality algebraically. ∣x+7∣≤8

Mathematics

1 answer:

AlekseyPX3 years ago

4 0

Answer:

x ≤ 1 and x ≥ −15

Step-by-step explanation:

Solving Absolute Value

We know that x + 7 ≤ 8 or x + 7 ≥ -8

Condition 1:

Step 1: Subtract 7 from both sides.

$x + 7 - 7\leq 8 - 7$
$x\leq 1$

Condition 2:

Step 1: Subtract 7 from both sides.

$x + 7 - 7\geq -8 - 7$
$x\geq -15$

Therefore, the answer is x ≤ 1 and x ≥ -15.

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Solve for r. r - 4.5 ≤ 11

erma4kov [3.2K]

Answer:

The answer is r < or equal to 15.5.

Step-by-step explanation:

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3 years ago

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Determine whether each integral is convergent or divergent. If it is convergent evaluate it. (a) integral from 1^(infinity) e^(-

AVprozaik [17]

Answer:

a) So, this integral is convergent.

b) So, this integral is divergent.

c) So, this integral is divergent.

Step-by-step explanation:

We calculate the next integrals:

$\int_1^{\infty} e^{-2x} dx=\left[-\frac{e^{-2x}}{2}\right]_1^{\infty}\\\\\int_1^{\infty} e^{-2x} dx=-\frac{e^{-\infty}}{2}+\frac{e^{-2}}{2}\\\\\int_1^{\infty} e^{-2x} dx=\frac{e^{-2}}{2}\\$

So, this integral is convergent.

$\int_1^{2}\frac{dz}{(z-1)^2}=\left[-\frac{1}{z-1}\right]_1^2\\\\\int_1^{2}\frac{dz}{(z-1)^2}=-\frac{1}{1-1}+\frac{1}{2-1}\\\\\int_1^{2}\frac{dz}{(z-1)^2}=-\infty\\$

So, this integral is divergent.

$\int_1^{\infty} \frac{dx}{\sqrt{x}}=\left[2\sqrt{x}\right]_1^{\infty}\\\\\int_1^{\infty} \frac{dx}{\sqrt{x}}=2\sqrt{\infty}-2\sqrt{1}\\\\\int_1^{\infty} \frac{dx}{\sqrt{x}}=\infty\\$

So, this integral is divergent.

4 0

3 years ago

What is an equation of the line that is perpendicular to −x+2y=4 and passes through the point (−2, 1) ?

Elza [17]

Answer:

y=-2x-3

Step-by-step explanation:

Since our equation is in standard form Ax+By=C we must first manipulate the equation so that we have it in the slope-intercept form such that y=mx+b. Therefore:

$-x+2y=4\\2y=x+4\\\\y=\frac{x+4}{2}\\\\y=\frac{1}{2}x+2$

Therefore, our slope is 1/2 and our y-intercept is 2. Now in order to determine a perpendicular line to the one stated above we must then get the negative inverse of our slope meaning $\frac{1}{2}=-2$ (negative reciprocal). Now we must use the point slope formula: